SysV-derived Unix does not have a stat command. Only the latest Solaris 11 has got it.
I would try perl.
leads to
for the stat() and localtime() functions.
I pasted the examples, and with a little trial and error I got
Now you can make it executable and run it with
These 3 Users Gave Thanks to MadeInGermany For This Post:
Hi,
I have a file say abc. I get the timestamp in following way:
ls -ltr abc | awk -F" " '{print $6,$7,$8}'
Mar 8 10:23
I need to get the timestamp as :
03-08-2007 10:23:00
Thanks
Sumeet (1 Reply)
hi everyone, im new here and am in desperate need of help. I want to convert my 32 bit unix time stamp ' 45d732f6' into a readable format (Sat, 17 February 2007 16:53:10 UTC) using c++.
I have looked around the interent but i just cant make sense of anything. All examples i can find just... (3 Replies)
Hi All,
I have a string like below.
"Mar 31 2009" .
I want to convert this to unix time .
Also please let me know how to find the unix time for the above string minus one day. For Eg. if i have string "Mar 31 2009" i want to find the unix time stamp of "Mar 30 2009".
Thanks in advance,... (11 Replies)
Hello,
How do I convert unix timestamp value to 'normal' date format - to get year month and day values ?
Looks like it's easy to do using GNU date (linux systems). But how do I do tthis on AIX ?
I don't want to write C program, any ways to do that using unix shells ?
thanks (1 Reply)
Hello Experts,
I have a timestamp(6) column in a .csv data file , format of the data is as below:-
ETCT,P,Elec, Inc.,abc,11/5/2010 4:16:09.000000 PM,Y,Y,Y
I want the timestamp column to be properly formatted like
11/05/2010 04:16:09.000000 PM
Currently the "0" is missing with... (3 Replies)
Hi all,
I'm a Unix newbie and I need to get file timestamp in the following format:
YYYYMMDD HH24:MM:SS
example:
20120713 18:49:30
For start I've tried the following code, but I don't know how to display the year and even format the date:
ls -l $filename | awk '{print $7 $6 $8}'
My... (4 Replies)
Hello I have a file : file1.txt with the below contents :
237176 test1 test2 1442149024
237138 test3 test4 1442121300
237171 test5 test7 1442112823
237145 test9 test10 1442109600
In the above file fourth field represents the timestamp in Unix format.
I found a command which converts... (6 Replies)
Hello All,
I have a date in DD/MM/YYYY format. I am trying to convert this into unix timestamp. I have tried following:
date -d $mydate +%s
where mydate = 23/12/2016 00:00:00
I am getting following error:
date: extra operand `+%s'
Try `date --help' for more information.
... (1 Reply)
Discussion started by: angshuman
1 Replies
LEARN ABOUT DEBIAN
time::y2038
Time::y2038(3pm) User Contributed Perl Documentation Time::y2038(3pm)NAME
Time::y2038 - Versions of Perl's time functions which work beyond 2038
SYNOPSIS
use Time::y2038;
print scalar gmtime 2**52; # Sat Dec 6 03:48:16 142715360
DESCRIPTION
On many computers, Perl's time functions will not work past the year 2038. This is a design fault in the underlying C libraries Perl uses.
Time::y2038 provides replacements for those functions which will work accurately +/1 142 million years.
This only imports the functions into your namespace. To replace it everywhere, see Time::y2038::Everywhere.
Replaces the following functions:
gmtime()
See "gmtime" in perlfunc for details.
localtime()
See "localtime" in perlfunc for details.
timegm()
my $time = timegm($sec, $min, $hour, $month_day, $month, $year);
The inverse of "gmtime()", takes a date and returns the coorsponding $time (number of seconds since Midnight, January 1st, 1970 GMT). All
values are the same as "gmtime()" so $month is 0..11 (January is 0) and the $year is years since 1900 (2008 is 108).
# June 4, 1906 03:02:01 GMT
my $time = timegm(1, 2, 3, 4, 5, 6);
timegm() can take two additional arguments which are always ignored. This lets you feed the results from gmtime() back into timegm()
without having to strip the arguments off.
The following is always true:
timegm(gmtime($time)) == $time;
timelocal()
my $time = timelocal($sec, $min, $hour, $mday, $month, $year);
my $time = timelocal($sec, $min, $hour, $mday, $month, $year, $wday, $yday, $isdst);
Like "timegm()", but interprets the date in the current time zone.
"timelocal()" will normally figure out if daylight savings time is in effect, but if $isdst is given this will override that check. This
is mostly useful to resolve ambiguous times around "fall back" when the hour between 1am and 2am occurs twice.
# Sun Nov 4 00:59:59 2007
print timelocal(59, 59, 0, 4, 10, 107); # 1194163199
# Sun Nov 4 01:00:00 2007 DST, one second later
print timelocal(0, 0, 1, 4, 10, 107, undef, undef, 1); # 1194163200
# Sun Nov 4 01:00:00 2007 no DST, one hour later
print timelocal(0, 0, 1, 4, 10, 107, undef, undef, 0); # 1194166800
$wday and $yday are ignored. They are only there for compatibility with the return value of "localtime()".
LIMITATIONS
The safe range of times is +/ 2**52 (about 142 million years).
Although the underlying time library can handle times from -2**63 to 2**63-1 (about +/- 292 billion years) Perl uses floating point numbers
internally and so accuracy degrates after 2**52.
BUGS & FEEDBACK
See http://rt.cpan.org/Dist/Display.html?Queue=Time-y2038 to report and view bugs.
If you like the module, please drop the author an email.
The latest version of this module can be found at http://y2038.googlecode.com/ and the repository is at
http://y2038.googlecode.com/svn/trunk/ in perl/Time-y2038. You have to check out the whole repository because there are symlinks.
AUTHOR
Michael G Schwern <schwern@pobox.com>
LICENSE & COPYRIGHT
Copyright 2008-2010 Michael G Schwern
This program is free software; you can redistribute it and/or modify it under the same terms as Perl itself.
See http://www.perl.com/perl/misc/Artistic.html
SEE ALSO
Time::y2038::Everywhere overrides localtime() and gmtime() across the whole program.
The y2038 project at http://y2038.googlecode.com/
<http://xkcd.com/376/>
perl v5.14.2 2011-11-15 Time::y2038(3pm)