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Top Forums Shell Programming and Scripting Remove duplicates separated by delimiter Post 303017781 by enrikS on Tuesday 22nd of May 2018 08:49:13 AM
Old 05-22-2018
Quote:
For some hints as to why your second code snippet didn't work, note that your awk code is specifying that the input field separator (FS) is a <tab> character, but there are no <tab>s in your sample input (just <space>s; no <tab>s). Therefore, your awk script is only seeing one input field; not eight. And split()ing an empty field (e.g., $6) produces an array with zero elements.
Spent hours trying to figure out why it was not working, All this because of misinterpretation of space for tab.

As for Col 6 or Col 7, all my strings are sorted. [The ones used in this example are not ]. As order of the output was not necessary, I did not mind when i ran the test this morning. But it good to know that it can be sort. Will edit the post to include that info.
.
One question in regards to
Code:
{for (n = split (P1, TMP, ","); n; n--)  T[TMP[n]]  
                                                              for (t in T)   {TX = TX DL t                                                                                          DL = ","    }

,

Don't know how to formulate it properly, just going to give an e.g
Code:
M3    C2    A1    D5    HH:FF    A1-A2,A5-A6,A1-A4    B4-B6,B2-B4,B1-B2

delete array if $3 is present
In this case $3 = A1, ; A1-A2 and A1-A4 must be removed.

So basically, before I saw your method, I put the 3rd column in a new text file, and search for these arrays. I was wondering if using your method is less complex. Hopefully this week end, will give it a try.
Im still learning how to write my codes using different approach. 3 weeks ago did not even know how to use linux lol Been so hard to comment and ask question on SO without being labeled [witch-hunt]. Glad I found this forum.










 

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JOIN(1) 						      General Commands Manual							   JOIN(1)

NAME
join - relational database operator SYNOPSIS
join [ options ] file1 file2 DESCRIPTION
Join forms, on the standard output, a join of the two relations specified by the lines of file1 and file2. If file1 is `-', the standard input is used. File1 and file2 must be sorted in increasing ASCII collating sequence on the fields on which they are to be joined, normally the first in each line. There is one line in the output for each pair of lines in file1 and file2 that have identical join fields. The output line normally con- sists of the common field, then the rest of the line from file1, then the rest of the line from file2. Fields are normally separated by blank, tab or newline. In this case, multiple separators count as one, and leading separators are dis- carded. These options are recognized: -an In addition to the normal output, produce a line for each unpairable line in file n, where n is 1 or 2. -e s Replace empty output fields by string s. -jn m Join on the mth field of file n. If n is missing, use the mth field in each file. -o list Each output line comprises the fields specified in list, each element of which has the form n.m, where n is a file number and m is a field number. -tc Use character c as a separator (tab character). Every appearance of c in a line is significant. SEE ALSO
sort(1), comm(1), awk(1) BUGS
With default field separation, the collating sequence is that of sort -b; with -t, the sequence is that of a plain sort. The conventions of join, sort, comm, uniq, look and awk(1) are wildly incongruous. 7th Edition April 29, 1985 JOIN(1)
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