Is it possible to have a pattern as RS in awk. For Example pl. go through the statement;
"
Account Serial Number: 88888888
TT00X000000XXXXXXXXXXXXX
SS00X000000XX.000,XXXXXXXXXXXXXXXXXX0000XXXXXXX0000000000
WW00X0000000XX000000000000MMMMMMM MMMMMMM0000AA11110000000000000000000000000... (1 Reply)
Hi ,
I want to assign a value to variable which will have size of the file that is
we have following files for eg:
ls -ltr
-rw-rw-r-- 1 dsadmin dstage 34 Oct 29 12:14 some.txt
-rw-rw-r-- 1 dsadmin dstage 0 Oct 29 14:52 eg.txt
-rwxrwxr-x 1 dsadmin dstage 1453 Oct... (2 Replies)
Hi,
Can some one please explain the following line please throw some light on the ones marked in red
awk '{print $9}' ${FTP_LOG} | awk -v start=${START_DATE} 'BEGIN { FS = "." } { old_line1=$0; gsub(/\-/,""); if ( $3 >= start ) print old_line1 }' | awk -v end=${END_DATE} 'BEGIN { FS="." } {... (3 Replies)
Hi Everyone,
When i issue command like
ls -l | awk '/udtts/ {print $9}'
===============================
I am getting output as
udttsGEHLNAR.6864
udttsGEHLNAR.7921
udttsNARALAX.15415
udttsNARALAX.18016
But I want output after dot i.e like
6864
7921
15415
18016 (3 Replies)
I have a set of multiple files out of which one i am showing below :
A0120110124102329 BED.
B01***DETALLADA 43984
The BO1 is the starting pattern of the second line. In the 2nd line in position 30,31,32 i need to replace 111, instead of 3... (2 Replies)
i have a log file where in i have 3 columns
a 11 test1
b 22 test2
in a script, i want to pass first column as an argument to awk so that i can get the second and third column respectively
Example : If i pass ($1 i.e 'a' to an awk, the result should be 11 test1)
i tried different awk... (2 Replies)
Dear all,
I find a shell script about awk command in the forum regarding
"Find and replace duplicate column values in a row"
In this thread, there is a command line as shown below to replace duplicate
awk -F, '{for (i=1;i<=NF;i++){if (v++){b=$i;$i=""}};print $0} END { print "dups are"... (1 Reply)
Hello again,
I have example config file with two arrays:
tab1="name1 surname1"
tab1="name2 surname2"
tab1="name3 surname3"
tab2="First"
tab2="Second"and csv file:
"aaaaa","surname1","name1","ddddd,eeeee","ffffff","ggggg","3","2012/02/22 12:25:21","2012/02/22... (7 Replies)
Hi,
I have a sample file in the following format.
000013560240|000013560240|001|P|155|99396|0||SS00325665|
000013560240|000013560240|002|P|17|99000|0||SS00325665|
000013560240|000013560240|002|F|-17|99000|0|R|SS00325665|
000013560240|000013560240|003|P|20|82270|0||SS00325665|... (3 Replies)
Discussion started by: nua7
3 Replies
LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1)NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS --predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO bup-midx(1), bup-save(1)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-margin(1)