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Top Forums Shell Programming and Scripting awk matching script not working as expected Post 303014847 by RudiC on Wednesday 21st of March 2018 07:53:07 PM
Old 03-21-2018
Quote:
Originally Posted by delbroooks
. . .
Code:
$ /bin/awk -V | head -n1
bash: /bin/awk: No such file or directory

Are you sure your script is starting at all?


Quote:
. . . find the best time available 5 minutes later (i. e. approximately)
What is "approximately 5 minutes later"? Within 5 min? Beyond 5 min? 10 sec / 30 sec / 100 sec within / beyond?

Quote:
. . . The expected output should look like this
Code:
 2018-02-16 16:42:53.926 farads 0.0000000000 2018-02-16 16:47:51.612 0.0006500000

Why the 612 ms, not the 611 ms entry?

Quote:
Code:
#!usr/bin/awk

You shebang might not work as it seems to be a relative path.

Quote:
Code:
{
  day=$1
  split($2, t, ".")
.
.
.
  t[3]=seconds"."t[2]
  records[t[3]]=$0
}

Is this ms precision to eliminate duplicate indices? ms wouldn't make sense if you're dealing with approximate 5 min?

Quote:
Code:
.
.
.
      min=(0 + "INF")              # whatever this means - it will yield min = 0
.
.
.
      if (difference < 0) difference=-difference
      if (difference < min) {
      min=difference
      matchfor[record]=records[others]
      }

.
.
.
With min = 0 and difference ALWAYS positive, the if branch will NEVER be entered. So - no surprise matchfor is undefined / uninitialized:

Quote:
Code:
awk: awkscript3:29: (FILENAME=- FNR=183) warning: reference to 
uninitialized element `matchfor["1518802491.175"]'
.
.
.

Would you mind to take a step back and rephrase your requirements? Like "For any given record take its time stamp, add five minutes, and from there find the line in the data file with the smallest absolute delta time and print it as a suffix to the actual line"

Last edited by RudiC; 03-21-2018 at 08:58 PM..
 

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