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Top Forums Shell Programming and Scripting Use script to mkdir based on file's data Post 303012710 by efsarantis on Wednesday 7th of February 2018 05:45:16 PM
Old 02-07-2018
I'm sorry i'm beginner in unix. I want to make a script in vi. My step is a variable $n given by the user.
I didn't post my attempts because they working totally wrong (probably i use wrong commands).

For directories i tried this:

Code:
 arr=($(cut -d ' ' -f1 < input.dat))
 mkdir $(for ((i=0;i<${#arr[@]};i=i+$n)); do echo ${arr[$i]-$arr[$i+$n]}; done)

and for files
Code:

awk ' f1  {n++}{print > "cat"n++"-"n++30".txt"}' input.dat


Last edited by Scrutinizer; 02-07-2018 at 06:53 PM.. Reason: code tags
 

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Perl::Critic::Policy::Variables::RequireNegativeIndices(User Contributed Perl DocumentPerl::Critic::Policy::Variables::RequireNegativeIndices(3pm)

NAME
Perl::Critic::Policy::Variables::RequireNegativeIndices - Negative array index should be used. AFFILIATION
This Policy is part of the core Perl::Critic distribution. DESCRIPTION
Conway points out that $arr[$#arr]; $arr[$#arr-1]; $arr[@arr-1]; $arr[@arr-2]; are equivalent to $arr[-1]; $arr[-2]; $arr[-1]; $arr[-2]; and the latter are more readable, performant and maintainable. The latter is because the programmer no longer needs to keep two variable names matched. This policy notices all of the simple forms of the above problem, but does not recognize any of these more complex examples: $some->[$data_structure]->[$#{$some->[$data_structure]} -1]; my $ref = @arr; $ref->[$#arr]; CONFIGURATION
This Policy is not configurable except for the standard options. AUTHOR
Chris Dolan <cdolan@cpan.org> COPYRIGHT
Copyright (c) 2006-2011 Chris Dolan. This program is free software; you can redistribute it and/or modify it under the same terms as Perl itself. perl v5.14.2 2012-06-07 Perl::Critic::Policy::Variables::RequireNegativeIndices(3pm)
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