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Top Forums Shell Programming and Scripting Need help on awk for printing the function name inside each function Post 303012108 by Sumanthsv on Tuesday 30th of January 2018 04:50:56 AM
Old 01-30-2018
Thanks a lot for the reply..

I have done using "sed" like below and its working fine.

Code:
func=`grep "()" Scriptname | cut -d "(" -f1`
for i in $func
do
sed  -i "/$i()/ {n;a\
echo $i
}" Scriptname
done

 

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ZGREP(1)                                                      General Commands Manual                                                     ZGREP(1)

NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code: (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. EXIT CODE
2 - An option that is not supported was specified. AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1) ZGREP(1)
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