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Full Discussion: Problem evaluating condition
Top Forums Shell Programming and Scripting Problem evaluating condition Post 303011957 by edstevens on Friday 26th of January 2018 02:07:12 PM
Old 01-26-2018
Rudic -
To show the "raw" value of $ORACLE_SID at a command line:

Code:
oracle:hr92upg$ echo $ORACLE_SID
hr92upg

And to show no hidden characters, I'll append an 'x' on each end:

Code:
oracle:hr92upg$ echo x${ORACLE_SID}x
xhr92upgx

And, as requested, the ps and grep, without the -v to filter out the grep itself

Code:
oracle:hr92upg$ ps -ef|grep pmon_$ORACLE_SID
oracle    1237     1  0 10:37 ?        00:00:01 ora_pmon_hr92upg
oracle   31557 28288  0 12:59 pts/0    00:00:00 grep pmon_hr92upg

And in the interest of full disclosure, all possible 'pmon' processes:

Code:
oracle:hr92upg$ ps -ef|grep pmon
oracle    1237     1  0 10:37 ?        00:00:01 ora_pmon_hr92upg
oracle    1631     1  0 Jan22 ?        00:00:46 ora_pmon_fs91dmo
oracle    2842     1  0 Jan22 ?        00:00:35 ora_pmon_fs91upg
oracle    4317     1  0 Jan22 ?        00:00:49 ora_pmon_fs91dev
oracle    9786     1  0 Jan04 ?        00:03:03 ora_pmon_fs92upg
oracle   10156     1  0 Jan04 ?        00:03:02 ora_pmon_hr92dev
oracle   21794     1  0 Jan05 ?        00:02:58 ora_pmon_fs92dev
oracle   23261     1  0 Jan25 ?        00:00:11 ora_pmon_hr92tst
oracle   31578 28288  0 12:59 pts/0    00:00:00 grep pmon

Compare the above with the list of possible values for ORACLE_SID generated at line 61 of my script, and displayed at line 63
 

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LEARN ABOUT DEBIAN

bup-margin

bup-margin(1)						      General Commands Manual						     bup-margin(1)

NAME

       bup-margin - figure out your deduplication safety margin

SYNOPSIS

       bup margin [options...]

DESCRIPTION

       bup margin  iterates  through  all  objects  in	your  bup repository, calculating the largest number of prefix bits shared between any two
       entries.  This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.

       For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45.  That  means  a  46-bit
       hash  would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
       its first 46 bits.

       The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects.  Since SHA-1 hashes have 160 bits,
       that  leaves 115 bits of margin.  Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
       with far fewer objects.

       If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see	if
       you're getting dangerously close to 160 bits.

OPTIONS

       --predict
	      Guess  the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
	      from the guess.  This is potentially useful for tuning an interpolation search algorithm.

       --ignore-midx
	      don't use .midx files, use only .idx files.  This is only really useful when used with --predict.

EXAMPLE

	      $ bup margin
	      Reading indexes: 100.00% (1612581/1612581), done.
	      40
	      40 matching prefix bits
	      1.94 bits per doubling
	      120 bits (61.86 doublings) remaining
	      4.19338e+18 times larger is possible

	      Everyone on earth could have 625878182 data sets
	      like yours, all in one repository, and we would
	      expect 1 object collision.

	      $ bup margin --predict
	      PackIdxList: using 1 index.
	      Reading indexes: 100.00% (1612581/1612581), done.
	      915 of 1612581 (0.057%)

SEE ALSO

       bup-midx(1), bup-save(1)

BUP

       Part of the bup(1) suite.

AUTHORS

       Avery Pennarun <apenwarr@gmail.com>.

Bup unknown-															     bup-margin(1)
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