awk question Post: 303010243

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awk question

I have the following error: ls -lt | awk 'BEGIN NR > 1 { print $2, $9 }' Syntax Error The source line is 1. The error context is BEGIN >>> NR <<< > 1 { print $2, $9 } awk: 0602-500 Quitting The source line is 1. What I want to do is ls a directory, skip the first...

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One more awk question!

Hello, I have the following command that does 2 searches. awk '{if ($0 ~ /STRING1/) {c++} }{if ( c == 2 ) {sub(/STRING1/,"NEWSTRING") } } { print }' FILE How do I search up after the first search? thanks

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i have a little awk script that I use looks this: awk '{if (FNR==1){print FILENAME; print $0}else print $0}' file1...file2....fi... > bundled. i have completely forgotten how to unbundle this. I have tried several different approaches and still can not remember how to unbundle the file bundled....

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I am trying to read through a file, gather the states in that file and change it from an abbreviation to the ful text. Can anyone provide some assistance. Thanks!!

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How I can rid of the following presentation du -sk /u*/oradata/TEST/*.dbf |awk '{print total+=$1} 1.28003e+06 4.35109e+06 4.36134e+06 4.4535e+06 5.47752e+06 5.48777e+06 7.52554e+06 7.73036e+06 9.06158e+06 :confused: thank you

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Hi, in the following script, what does " a=$0} END " mean ? do we need that ? Thanks awk '{a=$0} END {for (i=NR; i>=1; i--) print a}' file

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awk question

Can anyone help with this this one liner: nawk -v RS='' '$1=$1' InputFile What I have in the file: 0.0013985457223116 -0.0002338180925628 0.0 0.0003709430584958 -0.0005763523138347 0.0 And the output I want: 0.0013985457223116 -0.0002338180925628 0.0 0.0003709430584958...

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Basic awk question...getting awk to act on $1 of the command itself

I have a script problem that I am not able to solve due my very limited understanding of unix/awk. This is the contents of test.sh awk '{print $1}' From the prompt if I enter: ./test.sh Hello World I would expect to see "Hello" but all I get is a blank line. Only then if I enter "Hello...

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awk question.

Use and complete the template provided. The entire template must be completed. If you don't, your post may be deleted! 1. The problem statement, all variables and given/known data: im using ls -l | xargs | awk '{what ever files here}' im trying to get something that looks like this...

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awk question : system output to awk variable.

Hi Experts, I am trying to get system output to capture inside awk , but not working: Please advise if this is possible : I am trying something like this but not working, the output is coming wrong: echo "" | awk '{d=system ("date") ; print "Current date is:" , d }' Thanks,

LEARN ABOUT DEBIAN

colrm

COLRM(1)						    BSD General Commands Manual 						  COLRM(1)

NAME

     colrm -- remove columns from a file

SYNOPSIS

     colrm [start [stop]]

DESCRIPTION

     The colrm utility removes selected columns from the lines of a file.  A column is defined as a single character in a line.  Input is read
     from the standard input.  Output is written to the standard output.

     If only the start column is specified, columns numbered less than the start column will be written.  If both start and stop columns are spec-
     ified, columns numbered less than the start column or greater than the stop column will be written.  Column numbering starts with one, not
     zero.

     Tab characters increment the column count to the next multiple of eight.  Backspace characters decrement the column count by one.

ENVIRONMENT

     The LANG, LC_ALL and LC_CTYPE environment variables affect the execution of colrm as described in environ(7).

EXIT STATUS

     The colrm utility exits 0 on success, and >0 if an error occurs.

SEE ALSO

     awk(1), column(1), cut(1), paste(1)

HISTORY

     The colrm command appeared in 3.0BSD.

BSD
								  August 4, 2004							       BSD

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LEARN ABOUT DEBIAN

colrm