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Top Forums UNIX for Beginners Questions & Answers sed command to replace consecutive double quotes Post 303007733 by abhilashnair on Monday 20th of November 2017 11:00:23 PM
Old 11-21-2017
sed command to replace consecutive double quotes

I need to replace consecutive double quotes in a csv file, the data in the file is enclosed in double quotes but there are some places where the quotes are repeating
Example is below

Incoming data is :

Code:
"Pacific Region"|"PNG"|"Jimmy""|""|

Need output as:

Code:
"Pacific Region"|"PNG"|"Jimmy"|""|

Please Note that empty double quotes are perfectly valid here and I need to retain them

Last edited by Scrutinizer; 11-21-2017 at 12:30 AM.. Reason: code tags
 

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ESCAPESHELLARG(3)							 1							 ESCAPESHELLARG(3)

escapeshellarg - Escape a string to be used as a shell argument

SYNOPSIS
string escapeshellarg (string $arg) DESCRIPTION
escapeshellarg(3) adds single quotes around a string and quotes/escapes any existing single quotes allowing you to pass a string directly to a shell function and having it be treated as a single safe argument. This function should be used to escape individual arguments to shell functions coming from user input. The shell functions include exec(3), system(3) and the backtick operator. On Windows, escapeshellarg(3) instead removes percent signs, replaces double quotes with spaces and adds double quotes around the string. PARAMETERS
o $arg - The argument that will be escaped. RETURN VALUES
The escaped string. EXAMPLES
Example #1 escapeshellarg(3) example <?php system('ls '.escapeshellarg($dir)); ?> SEE ALSO
escapeshellcmd(3), exec(3), popen(3), system(3), backtick operator. PHP Documentation Group ESCAPESHELLARG(3)
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