Although this modifies and extends the specs in post#1, it doesn't make things much clearer. And, your code samples don't really help...
Wildly guessing / assuming that
- every record in in one single line
- "in between" means "in the same line"
- you want records with either keyword
- the keyword doesn't need to be listed in the output
, would this come close to what you need?
If it doesn't, please become way more specific with your description of the problem.
It would be highly appreciable if any one helps me in this. I am trying to get it done through Java but I love unix and believe it can be done within minutes with couple of lines.
The input log file is a text file contains multiple entries seperated by a blank line.
Each seperated entry... (7 Replies)
hello:
i have a file and i am trying to extract only unique words from that file.
i used the command: cat messages.1 | tr " " "\n" | sort | uniq -c
but using this command outputs everything unique in the file be it words, numbers, like all the characters..i need a command which will only... (6 Replies)
You are given a 1 year logfile with each line starting with a date in the form “YYYY-MM-DD”. How would you extract logs from the 4th day of each month and put them into a new file (1 Reply)
Hello,
I have a log file for the year, which contains lines starting with the data in the format of YYYY-MM-DD. I need to get all the lines that contain the DD being 04, how would I do this? I tried using grep "*-*04" but it didn't work.
Any quick one liners I should know about?
Thank you. (2 Replies)
I'm new to all this and I've been fiddling with this problem for HOURS and feel silly that I can't work it out!
I have a .log file that VERY long and looks like this:
2011-08-31 10:03:34 SUESTART AG Amndmnt Client WebRequest DNU SUEEND Sequence: 600,
2011-08-31 10:03:34 SUESTART... (11 Replies)
Hi all,
Hope someone here will be able to help me. Our system has some scripts that are run from a cron job every ten mins and is used to see how many error there are in that time frame. Problem is that in the scripts grep is used to find the data, but as the day goes on these log file grow to a... (7 Replies)
Hi
I am trying to extract data from within a log file and output format to a new file for further manipulation can someone provide script to do this?
For example I have a file as below and just want to extract all delimited variances of tag 32=* up to the delimiter "|" and output to a new file... (2 Replies)
I am running awk command to extract data from log file to calculate last 15 minutes log using below command and now i am getting bellow error:
awk '$0>=$from' from=$(`date -u +"####<%d-%b-%Y %H:%M:%S o'clock GMT>"-15min`) test.log
Error:
date: 0551-402 Invalid character in date/time... (8 Replies)
Hi
I have a daily rsync that runs and i am trying to find a easy way of extracting the start time and end time of the sync and extract the details of how much data was copied.
I would like to use this information to see if i can increase the amount of rsyncs that run in a day.
so the log... (3 Replies)
Discussion started by: treds
3 Replies
LEARN ABOUT PHP
zgrep
ZGREP(1) General Commands Manual ZGREP(1)NAME
zgrep - search possibly compressed files for a regular expression
SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename...
DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code:
(-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the
standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep.
If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.
EXIT CODE
2 - An option that is not supported was specified.
AUTHOR
Charles Levert (charles@comm.polymtl.ca)
SEE ALSO grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)ZGREP(1)