Hi All,
I need to find the previous month last day minus one day, using shell script. Can you guys help me to do this.
My Requirment is as below:
Input for me will be 2000909(YYYYMM)
I need the previous months last day minus 1 day timestamp. That is i need 2000908 months last day minus ... (3 Replies)
Hi
I have a table with name, date in format DD.MM.YYYY.
I need to something like this (I try to explain in pseudo code)
if SYSDATE (current date) minus 6 months > $expiry date
print OK
else print NOK with $name and $expiry date
I know this is possible with Oracle. How to do this... (0 Replies)
Hi guys,
I had a scenario...
1. I had to get the previous days date in yyyymmdd format
2. i had to create a file with Date inthe format yyyymmdd.txt format
both are different
thanks guys in advance.. (4 Replies)
I need to get the next day's date of the user entered date
for example:
Enter date (yyyy/mm/yy):
2013/10/08I need to get the next day's date of the user entered date
Desired Output:
2013/10/09Though there are ways to achieve this is Linux or Unix environment (date command) ,I need to... (1 Reply)
Hi there,
is it possible to get the actual date minux six months with just a simple command?
It's easy with Linux but on HP Unix (for me) impossible ;)
Best wishes (3 Replies)
I am running a script in ksh to get the 2 months back date from system date.The below code is giving correct date output from putty command prompt.But while running the script is .ksh file it is giving the error below.Please suggest.
; d=a; y=a
m-=num
while(m < 1) {m+=12; y--}... (1 Reply)
Hi the below code is failing i am trying to generate do the following:
2014-10-22 11:26:00 (Substract 24 hrs)
should produce
2014-10-21 11:26:00
I need the same formatting below because that gets inputted into code for an... (4 Replies)
I Have text like
XXX_20190908.csv.gz need to replace Only date in this format with current date every day
Thanks! (1 Reply)
Discussion started by: yamasani1991
1 Replies
LEARN ABOUT MINIX
date
DATE(1) General Commands Manual DATE(1)NAME
date - print or set the date and time
SYNOPSIS
date [-qsu] [[MMDDYY]hhmm[ss]] [+format]
OPTIONS -q Read the date from stdin
-s Set the time (implicit for -q or a date string)
-u Print the date as GMT
-t Use this number of seconds instead of current time
EXAMPLES
date # Print the date and time
date 0221921610 # Set date to Feb 21, 1992 at 4:10 p.m.
DESCRIPTION
With the -q flag or a numeric argument, date sets the GMT time and date. MMDDYY refers to the month, day, and year; hhmmss refers to the
hour, minute and second. Each of the six fields must be exactly two digits, no more and no less. date always display the date and time,
with the default format for the system. The -u flag request GMT time instead of local time. A format may be specified with a + followed
by a printf-like string with the following options:
%% % character
%A Name of the day
%B Name of the month
%D mm/dd/yy
%H Decimal hour on 2 digits
%I Decimal hour modulo 12 on 2 digits
%M Decimal minute on 2 digits
%S Decimal seconds on 2 digits
%T HH:MM:SS
%U Decimal week number, Sunday being first day of week
%W Decimal week number, Monday being first day of week
%X Same as %T
%Y Decimal year on 4 digits
%Z Time Zone (if any)
%a Abbreviated name of the day
%b Abbreviated name of the month
%c Appropriate date & time (default format)
%d Decimal day of the month on 2 digits
%e Same as %d, but a space replaces leading 0
%h Same as %b
%j Decimal dey of the year on 3 digits
%m Decimal month on 2 digits
%n Newline character
%p AM or PM
%r 12-hour clock time with AM/PM
%s Number of seconds since the epoch
%t Tab character
%w Decimal day of the week (0=Sunday)
%x Same as %D
%y Decimal year on 2 digits
SEE ALSO time(2), ctime(3), readclock(8).
DATE(1)