The line is simple, use " '{ print $1"]"$2"\"$3THE " NEEDS TO GO HERE$4 }'
I've tried \", "\, ^" and '"" but none of it works. What am I missing? Putting in the [ between $1 and $2 works fine, I just need to do the same with a ".
Thanks. (2 Replies)
Hi
What is the correct syntax for use a variable value within a print sentence :
Example:
VAR1=$1
VAR2=$2
ls -l $VAR2/*.LOG | grep -v $VAR1 | nawk -F " " '{ print "mv "$9 " /backup/BACKUP/backup_db_type/$VAR1_arch/."}' > move_arch_des.sh
Is this case i need to print $VAR1 within... (3 Replies)
Hello I have a log file like so
2009-01-15 17:55:06 H=host-216-153-217-114.spr.choiceone.net :30675 I=:25 F=<> rejected RCPT <feast@test.co.uk>: DNSBL listed at sbl-xbl.spamhaus.org
What I am trying to do is be able to print x amount of columns after a certain part of the line say F=
grep... (1 Reply)
Actually I got a list of file end with *.txt
I want to use the same command apply to all the *.txt
Thus I try to find out the fastest way to write those same command in a script and then want to let them run automatics.
For example:
I got the file below:
file1.txt
file2.txt
file3.txt... (4 Replies)
Hi friends I need one help from you .
I want to print name='JACK' through . how can i make it .
awk '{print "name=jack"}'
it ll print name=JACK (6 Replies)
Hi..
I have two files. contents of the files are as below.
header1.dat
-------------
This is a header record.
header2.dat
-------------
This is a header record.
Date:2011-01-05
I am executing the below scripts.
HEADER1=`cat header1.dat`
HEADER2=`cat header2.dat`
awk 'BEGIN... (2 Replies)
awk '{print "awk '{sub(/pdb_00/,"pdb_"$0"_00"); print}' pdb_"$0"_00.namd > tempo"; print "mv tempo pdb_"$0"_00.namd"}' datA2.dat > copy_script2.bash
This works when trying to print 'sed etc. etc' but if I switch to using AWK to print a set of AWK commands it doesn't work...
e.g. this... (3 Replies)
Hi,
My input files is like this
axis1 0 1 10
axis2 0 1 5
axis1 1 2 -4
axis2 2 3 -3
axis1 3 4 5
axis2 3 4 -1
axis1 4 5 -6
axis2 4 5 1
Now, these are my following tasks
1. Print a first column for every two rows that has the same value followed by a string.
2. Match on the... (3 Replies)
Hi,
I have the following input in a file & need output as mentioned below(need counter of every occurance of field which is to be increased by 1).
Input:
919143110065
919143110065
919143110052
918648846132
919143110012
918648873782
919143110152
919143110152
919143110152... (2 Replies)
Discussion started by: siramitsharma
2 Replies
LEARN ABOUT LINUX
colrm
COLRM(1) BSD General Commands Manual COLRM(1)NAME
colrm -- remove columns from a file
SYNOPSIS
colrm [start [stop]]
DESCRIPTION
The colrm utility removes selected columns from the lines of a file. A column is defined as a single character in a line. Input is read
from the standard input. Output is written to the standard output.
If only the start column is specified, columns numbered less than the start column will be written. If both start and stop columns are spec-
ified, columns numbered less than the start column or greater than the stop column will be written. Column numbering starts with one, not
zero.
Tab characters increment the column count to the next multiple of eight. Backspace characters decrement the column count by one.
ENVIRONMENT
The LANG, LC_ALL and LC_CTYPE environment variables affect the execution of colrm as described in environ(7).
EXIT STATUS
The colrm utility exits 0 on success, and >0 if an error occurs.
SEE ALSO awk(1), column(1), cut(1), paste(1)HISTORY
The colrm command appeared in 3.0BSD.
BSD August 4, 2004 BSD