Hi,
The scenario is as follow:
Backup was done using:
tar cvf /dev/rmt/0mn file1.ext
tar cvf /dev/rmt/0mn file2.ext
tar cvf /dev/rmt/0mn file3.ext
tar cvf /dev/rmt/0mn file4.ext
tar cvf /dev/rmt/0mn file5.ext
When I do; tar tvf /dev/rmt/0m,
it only gives me the first file on the... (1 Reply)
Good Day
I mistakely renamed the dld.sl file in the /usr/lib directory. When i try to ls/ftp into the box i get this error :eek:
crt0: ERROR couldn't open /usr/lib/dld.sl errno:000000002
I have tried to rename it back from the renamed file to the original file name, but it gives me the... (2 Replies)
When trying to copy a file in Solaris 8 it doesnt copy file or give a error. This worked 100% until the 29th. I've checked the rights and everything seems fine:
drwxrwxrwx 2 bmuser bmgroup 11776 Jan 3 10:32 spool
This is the file I want to copy:
-rwxrwxrwx 1 bmuser bmgroup ... (26 Replies)
Hii All,
I am using openldap v2.3 on redhat El-4. When i run ldapsearch it returns all the entries. The command runs successfully. But when I run the ldapsearch with following filter option it doesnt work and immediately returns to the shell.
ldapsearch uidNumber>=2000
I've started slapd... (0 Replies)
Hello
Im trying to extract this file
tar -xvf opt-samba-base.tar.tar
tar: 0511-169 A directory checksum error on media; 0 not equal to 75420.
but I get that message
I tried algo with gunzip and uncompress but nothing happens
gunzip -d opt-samba-base.tar.tar
gunzip:... (2 Replies)
It just does the break...even though the files are not the same...
# Compare extracts
#==========================================
count=0
while (( count < 5 ))
do
(( count+=1 ))
echo "Try $count"
file1=$(ls -l /tmp/psjava.xml|... (5 Replies)
Hi Guys,
I have a strange problem.( AIX 6.1) "vi" is not working at all..Whenever i #vi <anythin> ,, it returns the prompt back. Any clues folks?? (14 Replies)
I am trying to print out two fields in a file using awk. So, I have got
awk -F '\t' 'NF = 2 {print $1 $2 "]"}' two.txt
in a script called what.awk
When i run this version like this - ./what.awk then it runs however I want to run the program like this
awk -f what.awk two.txt.
When I... (8 Replies)
I am looping through a file in bash and performing some operations on it. Here is the code.
cat test.dat -
One
Two
Three
Case 1: With if inside while loop
Output:
One
file found :)
------------------
isn't it supposed to print following output !!!
one (3 Replies)
Discussion started by: qwarentine
3 Replies
LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1)NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS --predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO bup-midx(1), bup-save(1)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-margin(1)