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Top Forums Shell Programming and Scripting How to remove part of the line from start of the line? Post 302998070 by Don Cragun on Wednesday 24th of May 2017 09:15:20 PM
Old 05-24-2017
Actually, you can do this in awk without a temporary file because this is a special case:
Code:
awk '{sub(/\r/,""); print $NF > FILENAME; exit}' Input_file

The special case works only when awk has already read everything it needs from your input file before it attempts to write anything back to your input file and quits before trying to read anything else.
This User Gave Thanks to Don Cragun For This Post:
 

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IGAWK(1)							 Utility Commands							  IGAWK(1)

NAME
igawk - gawk with include files SYNOPSIS
igawk [ all gawk options ] -f program-file [ -- ] file ... igawk [ all gawk options ] [ -- ] program-text file ... DESCRIPTION
Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1). AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like @include getopt.awk in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path. OPTIONS
See gawk(1) for a full description of the AWK language and the options that gawk supports. EXAMPLES
cat << EOF > test.awk @include getopt.awk BEGIN { while (getopt(ARGC, ARGV, "am:q") != -1) ... } EOF igawk -f test.awk SEE ALSO
gawk(1) Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995. AUTHOR
Arnold Robbins (arnold@skeeve.com). Free Software Foundation Nov 3 1999 IGAWK(1)
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