05-20-2017
And what does "02/04/17" represent? Would be valuable to know if we want to automate anything.
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Any ideas?
1)loop through text file
2)extract everything between SOL and EOL
3)output files, for example: 123.txt and 124.txt for the file below
So far I have: sed -n "/SOL/,/EOL/{p;/EOL/q;}" file
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SOL-123.go
something goes here
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Shell script for the below operation :
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SEQ++1'
MOA+9:000,00:ABC'
RFF+AIK:000000007'
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NAD+PL+++XXXXXXXXXXX XXXXXXX XX++XXX XXXX XXXX X.X. XXXXXXXXX+++NL'
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I have a text file:
router1#sh ip blah blah | incl ---
Gi2/8 10.60.4.181 --- 10.60.123.175 11 0000 0000 355K
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I have a text file in the following format:
13412 NA06985 0 0 2 46.6432798439 4 4 4 4
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Hi,
I have a text file in the following format:
Code:
13412 NA06985 0 0 2 46.6432798439 4 4 4 4
13412 NA06991 NA06993 NA06985 2 48.8478948517 4 4 2 4
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7. Programming
I was trying to parse the text file, which will looks like this
###XYZABC####
############
int = 4
char = 1
float = 1
.
.
############
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I'm totally stumped with how to handle this huge text file I'm trying to deal with. I really need some help!
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ab1ba67c331a3d731396322fad8dd71a3b627f89359827697645c806091c40b9
0.2
812a3c3684310045f1cb3157bf5eebc4379804e98c82b56f3944564e7bf5dab5
0.6
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Hi Friends,
I am back for the second round today - :D
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Home
friends
friendship meter
Tools
Mirrors
Downloads
My Data
About Us
Help
My own results
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I have a text file with records of the form:
A X1 Y1 X2 Y2 X3 Y3
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A X1 Y1
A X2 Y2
A X3 Y3
etc
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A64L(3) Linux Programmer's Manual A64L(3)
NAME
a64l, l64a - convert between long and base-64
SYNOPSIS
#include <stdlib.h>
long a64l(char *str64);
char *l64a(long value);
DESCRIPTION
These functions provide a conversion between 32-bit long integers and little-endian base-64 ASCII strings (of length zero to six). If the
string used as argument for a64l() has length greater than six, only the first six bytes are used. If longs have more than 32 bits, then
l64a() uses only the low order 32 bits of value, and a64l() sign-extends its 32-bit result.
The 64 digits in the base 64 system are:
'.' represents a 0
'/' represents a 1
0-9 represent 2-11
A-Z represent 12-37
a-z represent 38-63
So 123 = 59*64^0 + 1*64^1 = "v/".
NOTES
The value returned by a64l() may be a pointer to a static buffer, possibly overwritten by later calls.
The behaviour of l64a() is undefined when value is negative. If value is zero, it returns an empty string.
These functions are broken in glibc before 2.2.5 (puts most significant digit first).
CONFORMING TO
XPG 4.2, POSIX 1003.1-2001.
SEE ALSO
uuencode(1), itoa(3), strtoul(3)
2002-02-15 A64L(3)