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Top Forums Shell Programming and Scripting Parsing the longest match substring Post 302992810 by Don Cragun on Wednesday 1st of March 2017 11:29:46 PM
Old 03-02-2017
You state that the desired match for the input:
Code:
(\\b-[pt22dx]dfdfs/(dsgfspp22dx//[(\pp22dx)-@@----B-@--

is pp22dx instead of pp22 because pp22dx is longer. But why isn't pt22dx just as valid as pp22dx? (Both appear in the input file named primary, both are the same length, and pt22dx appears on that line of input before pp22dx.)

Assuming either input is allowed, you could try something like:
Code:
awk -F// -v OFS="\t\t" '
FNR == NR {
	if((l = length($0)) in pat) {
		pat[l] = pat[l] "|" $0
		next
	}
	pat[l] = $0
	for(i = 1; i <= nl && lengths[i] > l; i++)
		new[i] = lengths[i]
	new[i] = l
	for(; i <= nl; i++)
		new[i + 1] = lengths[i]
	nl++
	for(i = 1; i <= nl; i++)
		lengths[i] = new[i]
	next
}
{	for(i = 1; i <= nl; i++)
		if(match($1, pat[lengths[i]])) {
			print $0, substr($1, RSTART, RLENGTH)
			next
		}
	print $0, "No match"
}' primary scrambled

which with your sample inputs produces the output:
Code:
())[pt22dx]dfdfs//(dsgfspp22dx/pg22dx)-signal		pt22dx
(\\b-[pt22dx]dfdfs/(dsgfspp22dx//[(\pp22dx)-@@----B-@--		pt22dx
signal-ef##$@pp22//[[((dsgfspp22dx/pg22dx)-signal[(\pp22dx)-@@----B-@--		pp22

The above code just uses awk features defined by the standards. If someone wants to try this on a Solaris/SunOS system, change awk to /usr/pg4/bin/awk or nawk. Sorting the lengths array might be done more efficiently with built-in functions in some versions of awk.
This User Gave Thanks to Don Cragun For This Post:
 

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