Hi,
I have a script which takes a value from a file and performs calculations on it. Trouble is that this value is a float not an integer and it errors at the decimal point!
eg. 94.62
I would like to be able to detect the length of the float (in this above case, 5 characters), and simply do a... (2 Replies)
Hi ...
I am trying to calculate the time needed for a command to execute..
but the resulting value is getting as string..
so i am not able to use "expr " command..
please help me to convert the value to integer so that i can proceed with my script..
Regards
esham (1 Reply)
Hi,
I am passing a variable to a unix function.
However when I try to assign the value to another variable like
typeset -i I_CACHE_VAL=$2
Is this because of String to Integer conversion?
I get an error.
Please help me with thsi.
Thanks (2 Replies)
Hi everyone,
I would like to know how to convert an integer to a string. for instance if i=1 i would like to creat a variable called constant1. i want to do this in a for loop so for each value of i, i create a new variable such as constant2, constant3,... and so on.
for i in 1 2 3
do ... (1 Reply)
I'm attempting to read a file that is composed of complex 32-bit floating point values on Solaris 10 that came from a 64-bit Red Hat computer.
When I first tried reading the file, it looked like there was a byte-swapping problem and after running the od command on the file Solaris and Red Hat... (2 Replies)
okay so i run an openssl command to get the date of an expired script. Doing so gives me this:
enddate=Jun 26 23:59:59 2012 GMT
Then i cut everything out and just leave the month which is "Jun"
Now the next part of my script is to tell the user if the the certificate is expired or not... (6 Replies)
Dear community,
i got a problem to get "date +%j" as the right value.
Today is the 10th day of the year.
#./script.sh 2
#!/bin/bash/
Var1=$(date +%j)
Var2=$1
let result=$Var1+$Var2
echo $Var1 plus $Var2 equals $result
The output of the script is:
010 plus 2 equals 10... (9 Replies)
I have a function that is supposed to check for user processes and wait for 0 count before exiting the function. I am sure I have more than one issue in my code, but the stumbling block right now is that I am trying to convert the value of my variable from a string to integer.
process_count... (10 Replies)
Discussion started by: MIA651
10 Replies
LEARN ABOUT PHP
debug_zval_dump
DEBUG_ZVAL_DUMP(3) 1 DEBUG_ZVAL_DUMP(3)debug_zval_dump - Dumps a string representation of an internal zend value to outputSYNOPSIS
void debug_zval_dump (mixed $variable, [mixed $...])
DESCRIPTION
Dumps a string representation of an internal zend value to output.
PARAMETERS
o $variable
- The variable being evaluated.
RETURN VALUES
No value is returned.
EXAMPLES
Example #1
debug_zval_dump(3) example
<?php
$var1 = 'Hello World';
$var2 = '';
$var2 =& $var1;
debug_zval_dump(&$var1);
?>
The above example will output:
&string(11) "Hello World" refcount(3)
Note
Beware the refcount
The refcount value returned by this function is non-obvious in certain circumstances. For example, a developer might expect the
above example to indicate a refcount of 2. The third reference is created when actually calling debug_zval_dump(3).
This behavior is further compounded when a variable is not passed to debug_zval_dump(3) by reference. To illustrate, consider a
slightly modified version of the above example:
Example #2
<?php
$var1 = 'Hello World';
$var2 = '';
$var2 =& $var1;
debug_zval_dump($var1); // not passed by reference, this time
?>
The above example will output:
string(11) "Hello World" refcount(1)
Why refcount(1)? Because a copy of $var1 is being made, when the function is called.
This function becomes even more confusing when a variable with a refcount of 1 is passed (by copy/value):
Example #3
<?php
$var1 = 'Hello World';
debug_zval_dump($var1);
?>
The above example will output:
string(11) "Hello World" refcount(2)
A refcount of 2, here, is extremely non-obvious. Especially considering the above examples. So what's happening?
When a variable has a single reference (as did $var1 before it was used as an argument to debug_zval_dump(3)), PHP's engine opti-
mizes the manner in which it is passed to a function. Internally, PHP treats $var1 like a reference (in that the refcount is
increased for the scope of this function), with the caveat that if the passed reference happens to be written to, a copy is made,
but only at the moment of writing. This is known as "copy on write."
So, if debug_zval_dump(3) happened to write to its sole parameter (and it doesn't), then a copy would be made. Until then, the
parameter remains a reference, causing the refcount to be incremented to 2 for the scope of the function call.
SEE ALSO var_dump(3), debug_backtrace(3), References Explained, References Explained (by Derick Rethans).
PHP Documentation Group DEBUG_ZVAL_DUMP(3)