Sponsored Content
Top Forums Shell Programming and Scripting Print field after pattern in all lines Post 302988839 by Akshay Hegde on Tuesday 3rd of January 2017 01:35:25 PM
Old 01-03-2017
Try, works with current data

Code:
akshay@db-3325:/tmp$ cat f
hello--hello1--hello2--#growncars#vello--hello3--hello4--jello#growncars#dello--gello--gelloA--gelloB#growncars#

Code:
akshay@db-3325:/tmp$ awk '$0==p{s=1;next}s && NF; $0==p{s=0}' RS="#" p="growncars" f
vello--hello3--hello4--jello
dello--gello--gelloA--gelloB

This User Gave Thanks to Akshay Hegde For This Post:
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Print line if first Field matches a pattern

Hi All, I would like my code to be able to print out the whole line if 1st field has a dot in the number. Sample input and expected output given below. My AWK code is below but it can;t work, can any expert help me ? Thanks in advance. {if ($1 ~ /*\.*/) { print $0 }} Input: ... (2 Replies)
Discussion started by: Raynon
2 Replies

2. Shell Programming and Scripting

Print lines where there's no indent on the first field

Hi All, I need a code to print those lines where there's NO indents on the 1st field Example shown below. I tried to use the below codes but i am not able to see the expected result. Can any expert give any advise ? My Code cat filename| awk '$1 ~ /^+$/ {print $0}' Input 1199 ... (7 Replies)
Discussion started by: Raynon
7 Replies

3. Shell Programming and Scripting

print the last line of an recurring pattern on the 3rd field

How can i awk/sed to print the last line of an recurring pattern on the 3rd field? Input lines: 123456.1 12 1357911 11111.1 01 123456.2 12 1357911 11111.2 02 123456.3 12 1357911 11111.3 03 123456.4 12 1357911 11111.4 04 123456.5 12 1357911 11111.5 05 246810.1 12 1357911 22222.1 01... (4 Replies)
Discussion started by: ux4me
4 Replies

4. Shell Programming and Scripting

print lines up to pattern excluding pattern

11 22 33 44 55 66 77 When pattern 55 is met, print upto it, so output is 11 22 33 44 (1 Reply)
Discussion started by: anilcliff
1 Replies

5. UNIX for Dummies Questions & Answers

Match pattern in a field, print pattern only instead of the entire field

Hi ! I have a tab-delimited file, file.tab: Column1 Column2 Column3 aaaaaaaaaa bbtomatoesbbbbbb cccccccccc ddddddddd eeeeappleseeeeeeeee ffffffffffffff ggggggggg hhhhhhtomatoeshhh iiiiiiiiiiiiiiii ... (18 Replies)
Discussion started by: lucasvs
18 Replies

6. Shell Programming and Scripting

Need one liner to search pattern and print everything expect 6 lines from where pattern match made

i need to search for a pattern from a big file and print everything expect the next 6 lines from where the pattern match was made. (8 Replies)
Discussion started by: chidori
8 Replies

7. Shell Programming and Scripting

Awk: print lines with one of multiple pattern in the same field (column)

Hi all, I am new to using awk and am quickly discovering what a powerful pattern-recognition tool it is. However, I have what seems like a fairly basic task that I just can't figure out how to perform in one line. I want awk to find and print all the lines in which one of multiple patterns (e.g.... (8 Replies)
Discussion started by: elgo4
8 Replies

8. Shell Programming and Scripting

Print ALL lines except if field is 999

Hi All!!! :-) I need a command that will print each line of a text file UNLESS the 3rd field of that line is equal to the number 999. (space seperated fields) Solaris10/BASH SHELL: INPUT.TXT aaa bbb 111 222 ccc ddd 333 444 eee fff 999 555 ggg hhh 666 777 aaa bbb 999 222 ccc ddd 333... (7 Replies)
Discussion started by: ajp7701
7 Replies

9. Shell Programming and Scripting

Match Pattern and print pattern and multiple lines into one line

Hello Experts , require help . See below output: File inputs ------------------------------------------ Server Host = mike id rl images allocated last updated density vimages expiration last read <------- STATUS ------->... (4 Replies)
Discussion started by: tigerhills
4 Replies

10. Shell Programming and Scripting

sed -- Find pattern -- print remainder -- plus lines up to pattern -- Minus pattern

The intended result should be : PDF converters 'empty line' gpdftext and pdftotext?xml version="1.0"?> xml:space="preserve"><note-content version="0.1" xmlns:/tomboy/link" xmlns:size="http://beatniksoftware.com/tomboy/size">PDF converters gpdftext and pdftotext</note-content>... (9 Replies)
Discussion started by: Klasform
9 Replies
bup-margin(1)						      General Commands Manual						     bup-margin(1)

NAME
bup-margin - figure out your deduplication safety margin SYNOPSIS
bup margin [options...] DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids. For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by its first 46 bits. The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits, that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits with far fewer objects. If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if you're getting dangerously close to 160 bits. OPTIONS
--predict Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer from the guess. This is potentially useful for tuning an interpolation search algorithm. --ignore-midx don't use .midx files, use only .idx files. This is only really useful when used with --predict. EXAMPLE
$ bup margin Reading indexes: 100.00% (1612581/1612581), done. 40 40 matching prefix bits 1.94 bits per doubling 120 bits (61.86 doublings) remaining 4.19338e+18 times larger is possible Everyone on earth could have 625878182 data sets like yours, all in one repository, and we would expect 1 object collision. $ bup margin --predict PackIdxList: using 1 index. Reading indexes: 100.00% (1612581/1612581), done. 915 of 1612581 (0.057%) SEE ALSO
bup-midx(1), bup-save(1) BUP
Part of the bup(1) suite. AUTHORS
Avery Pennarun <apenwarr@gmail.com>. Bup unknown- bup-margin(1)
All times are GMT -4. The time now is 10:58 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy