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Could you please try following and let me know if this helps you.
Output will be as follows.
So if you run code date -d '($YESTERDAY)' +"%s000" or date -d 0 +"%s000" both will give same result as 1482814800000, so you could get it as it is taking it's value as 0 for '($YESTERDAY)'.
Kindly do let me know if this helps you.
Thanks,
R. Singh
This User Gave Thanks to RavinderSingh13 For This Post:
Hi,
I wish to display date say 25th Jan, 2008 in format '25-1-2008'
i.e. month should be displayed as '1' and not '01'.
I wish that 0 should not be displayed in month.
Thanks
Rochit (4 Replies)
Dear all
I am bit new to programming. I have to redirect the output to a file which will be in the following format
man ls> date +"hup-%m%d%y-%H%M" --------> this will show me the month,day,year,hours and minute in a file name whose name start from "hup-"
kindly any correct my syntax (2 Replies)
I want to get previous date from date command. I am using ksh shell.
Exmp:
today is 2008.09.04
I want the result : 2008.09.03
Please help.
Thanks in advance. (4 Replies)
Hii.. Everyone :
I have 15 Sun Servers with Solaris-10, Now on some of the servers when
I execuit the command "date" I get following o/p :
# date
Wed Sep 10 22:29:37 IST 2008
And on some of Servers I am getting :
# date
Wednesday, September 10, 2008 10:23:47 PM IST
Kindly see... (3 Replies)
Hi
I have one problem with cron job in Control Panel.
I have a log file that is created once a day on another server and I need to transfer it in an exact time to my server so I wrote the cron job for it BUT the problem is in the date command:
/filelog-`date +%Y-%m-%d`.tar.gz;
The file... (1 Reply)
Hi all,
Need an urgent help on the below scenario.
script:
awk -F","
'BEGIN { #some variable assignment}
{ #some calculation and put values in array}
END {
year=#getting it from array and assume this will be 2014
month=#getting it from array and this will be 05
date=#... (7 Replies)
HI,
Can anyone tell me how to pull the date and file name separated by a space using the find command or any other command. I want to look through several directories and based on a date timeframe (find -mtime -7), output the file name (without the path) and the date(in format mmddyyyy) to a... (2 Replies)
current date command runs well
awk -v t="$(date +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
subtract 30 days fails
awk -v t="$(date --date="-30days" +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
awk command in hp unix subtract 30 days automatically from current date without date illegal option error... (20 Replies)
Discussion started by: kmarcus
20 Replies
LEARN ABOUT DEBIAN
mojo::date
Mojo::Date(3pm) User Contributed Perl Documentation Mojo::Date(3pm)NAME
Mojo::Date - HTTP 1.1 date container
SYNOPSIS
use Mojo::Date;
my $date = Mojo::Date->new(784111777);
my $http_date = $date->to_string;
$date->parse('Sun, 06 Nov 1994 08:49:37 GMT');
my $epoch = $date->epoch;
DESCRIPTION
Mojo::Date implements HTTP 1.1 date and time functions according to RFC 2616.
Sun, 06 Nov 1994 08:49:37 GMT ; RFC 822, updated by RFC 1123
Sunday, 06-Nov-94 08:49:37 GMT ; RFC 850, obsoleted by RFC 1036
Sun Nov 6 08:49:37 1994 ; ANSI C's asctime() format
ATTRIBUTES
Mojo::Date implements the following attributes.
"epoch"
my $epoch = $date->epoch;
$date = $date->epoch(784111777);
Epoch seconds.
METHODS
Mojo::Date inherits all methods from Mojo::Base and implements the following new ones.
"new"
my $date = Mojo::Date->new;
my $date = Mojo::Date->new($string);
Construct a new Mojo::Date object.
"parse"
$date = $date->parse('Sun Nov 6 08:49:37 1994');
Parse date in one of the following formats.
- Epoch format(784111777)
- RFC 822/1123 (Sun, 06 Nov 1994 08:49:37 GMT)
- RFC 850/1036 (Sunday, 06-Nov-94 08:49:37 GMT)
- ANSI C asctime() (Sun Nov 6 08:49:37 1994)
"to_string"
my $string = $date->to_string;
Render date suitable for HTTP 1.1 messages.
SEE ALSO
Mojolicious, Mojolicious::Guides, <http://mojolicio.us>.
perl v5.14.2 2012-09-05 Mojo::Date(3pm)