Hi,
I wish to display date say 25th Jan, 2008 in format '25-1-2008'
i.e. month should be displayed as '1' and not '01'.
I wish that 0 should not be displayed in month.
Thanks
Rochit (4 Replies)
Dear all
I am bit new to programming. I have to redirect the output to a file which will be in the following format
man ls> date +"hup-%m%d%y-%H%M" --------> this will show me the month,day,year,hours and minute in a file name whose name start from "hup-"
kindly any correct my syntax (2 Replies)
I want to get previous date from date command. I am using ksh shell.
Exmp:
today is 2008.09.04
I want the result : 2008.09.03
Please help.
Thanks in advance. (4 Replies)
Hii.. Everyone :
I have 15 Sun Servers with Solaris-10, Now on some of the servers when
I execuit the command "date" I get following o/p :
# date
Wed Sep 10 22:29:37 IST 2008
And on some of Servers I am getting :
# date
Wednesday, September 10, 2008 10:23:47 PM IST
Kindly see... (3 Replies)
Hi
I have one problem with cron job in Control Panel.
I have a log file that is created once a day on another server and I need to transfer it in an exact time to my server so I wrote the cron job for it BUT the problem is in the date command:
/filelog-`date +%Y-%m-%d`.tar.gz;
The file... (1 Reply)
Hi all,
Need an urgent help on the below scenario.
script:
awk -F","
'BEGIN { #some variable assignment}
{ #some calculation and put values in array}
END {
year=#getting it from array and assume this will be 2014
month=#getting it from array and this will be 05
date=#... (7 Replies)
HI,
Can anyone tell me how to pull the date and file name separated by a space using the find command or any other command. I want to look through several directories and based on a date timeframe (find -mtime -7), output the file name (without the path) and the date(in format mmddyyyy) to a... (2 Replies)
current date command runs well
awk -v t="$(date +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
subtract 30 days fails
awk -v t="$(date --date="-30days" +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
awk command in hp unix subtract 30 days automatically from current date without date illegal option error... (20 Replies)
Discussion started by: kmarcus
20 Replies
LEARN ABOUT PHP
gmdate
GMDATE(3) 1 GMDATE(3)gmdate - Format a GMT/UTC date/time
SYNOPSIS
string gmdate (string $format, [int $timestamp = time()])
DESCRIPTION
Identical to the date(3) function except that the time returned is Greenwich Mean Time (GMT).
PARAMETERS
o $format
- The format of the outputted date string. See the formatting options for the date(3) function.
o $timestamp
- The optional $timestamp parameter is an integer Unix timestamp that defaults to the current local time if a $timestamp is not
given. In other words, it defaults to the value of time(3).
RETURN VALUES
Returns a formatted date string. If a non-numeric value is used for $timestamp, FALSE is returned and an E_WARNING level error is emitted.
CHANGELOG
+--------+---------------------------------------------------+
|Version | |
| | |
| | Description |
| | |
+--------+---------------------------------------------------+
| 5.1.0 | |
| | |
| | The valid range of a timestamp is typically from |
| | Fri, 13 Dec 1901 20:45:54 GMT to Tue, 19 Jan 2038 |
| | 03:14:07 GMT. (These are the dates that corre- |
| | spond to the minimum and maximum values for a |
| | 32-bit signed integer). However, before PHP 5.1.0 |
| | this range was limited from 01-01-1970 to |
| | 19-01-2038 on some systems (e.g. Windows). |
| | |
| 5.1.1 | |
| | |
| | There are useful constants of standard date/time |
| | formats that can be used to specify the $format |
| | parameter. |
| | |
+--------+---------------------------------------------------+
EXAMPLES
Example #1
gmdate(3) example
When run in Finland (GMT +0200), the first line below prints "Jan 01 1998 00:00:00", while the second prints "Dec 31 1997
22:00:00".
<?php
echo date("M d Y H:i:s", mktime(0, 0, 0, 1, 1, 1998));
echo gmdate("M d Y H:i:s", mktime(0, 0, 0, 1, 1, 1998));
?>
SEE ALSO date(3), mktime(3), gmmktime(3), strftime(3).
PHP Documentation Group GMDATE(3)