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Full Discussion: A little bit of XMAS fun...
The Lounge What is on Your Mind? A little bit of XMAS fun... Post 302988371 by bakunin on Sunday 25th of December 2016 10:16:37 AM
Old 12-25-2016
OK, first establish the constants:

beer-bottle=10, hamburger=5, beer-glass=2, hot dog=x

So we have the integral from 0 to infinity of 10sin(x) / 2x dx. This (the so-called "Dirichlet-Integral") is an improper integral. As the integral from 0 to infinity of sin( \omega ) / \omega d\omega = \pi/2 we get 5 \pi / 2 or, after applying the linguistic uncertainty-relation ("pi" => "pie"):

two pies and a half.

bakunin

Last edited by bakunin; 12-25-2016 at 05:49 PM..
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MODF(3) 						     Linux Programmer's Manual							   MODF(3)

NAME
modf, modff, modfl - extract signed integral and fractional values from floating-point number SYNOPSIS
#include <math.h> double modf(double x, double *iptr); float modff(float x, float *iptr); long double modfl(long double x, long double *iptr); Link with -lm. Feature Test Macro Requirements for glibc (see feature_test_macros(7)): modf(), modl(): _BSD_SOURCE || _SVID_SOURCE || _XOPEN_SOURCE >= 600 || _ISOC99_SOURCE; or cc -std=c99 DESCRIPTION
The modf() function breaks the argument x into an integral part and a fractional part, each of which has the same sign as x. The integral part is stored in the location pointed to by iptr. RETURN VALUE
The modf() function returns the fractional part of x. If x is a NaN, a NaN is returned, and *iptr is set to a NaN. If x is positive infinity (negative infinity), +0 (-0) is returned, and *iptr is set to positive infinity (negative infinity). ERRORS
No errors occur. CONFORMING TO
C99, POSIX.1-2001. The variant returning double also conforms to SVr4, 4.3BSD, C89. SEE ALSO
frexp(3), ldexp(3) COLOPHON
This page is part of release 3.25 of the Linux man-pages project. A description of the project, and information about reporting bugs, can be found at http://www.kernel.org/doc/man-pages/. 2008-08-05 MODF(3)
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