Hi ,
could any one suggest me that how to determine if the first field is numeric and if it is greater than another number then from that point everything else should be printed using awk.
I have tried this
:
awk -v xxxx=$xxxxx '
BEGIN {
enable=0
}
{
print $1
if ( ( $1 !~ "^*$" ... (5 Replies)
Hi all,
I need help in following scenario. I have a file with about 10,000 lines. There are several lines which have word "START" (all upper case) in them. I want to grep line with word "START" and then do the following
1. Print the line number having word "START"
2. Print the next 11 lines.
... (4 Replies)
Hi, i was looking for unix command(s) for :
find the first occurrence of a given pattern with in a file and print the remaining part.
below is an example of what i am looking for:
lets say, a file named myfile.txt
now, the command i am looking for will do the following (4 Replies)
Hi folks
I am not allowed to install GNU grep on AIX.
Here my code excerpt:
grep_fatal () {
/usr/sfw/bin/gegrep -B4 -A2 "FATAL|QUEUE|SIGHUP"
}
Howto the same on AIX based machine?
from manual GNU grep
‘--after-context=num’
Print num lines of trailing context after... (4 Replies)
I have several very large file that are extracts from Oracle tables. These files are formatted in XML type syntax with multiple entries like:
<ROW>
some information
more information
</ROW>
I want to grep for some words, then print all lines between <ROW> AND </ROW>. Can this be done with AWK?... (7 Replies)
Hi,
i would like to get the above and below lines of the grep pattern .
For ex :
file as below:
chk1- aaaa
1-Nov
chk2 -aaaa
##########
chk1-bbbbbb
1-Nov
chk2-bbbbbb
#########
my search pattern is date : 1-Nov
i need the o/p as below
chk1- aaaa
1-Nov (6 Replies)
Hi
I have this in my file
2011-04-18 15:32:11 system-alert-00012: UDP flood! From xxxxxx to yyyyyyyyyy, int ethernet0/2). Occurred 1 times.
2011-04-18 15:32:11 system-alert-00012: UDP flood! From xxxxxx to yyyyyyyyyy, int ethernet0/2). Occurred 1 times.
2011-04-18 15:32:11... (9 Replies)
Hi ,
My record file , need to print up to above (DATA array)(there may be n no lines ) , grep "myvalue" row now .....suggest me some options
--- DATA Array---
record type xxxxx
sequence type yyyyy
2
3---> data1
/dev/
--- DEVICE ---
MAXIMUM_People=
data_blocks=
MY_value=2
xyz
abc ... (0 Replies)
Hello there
I'd like to make a copy of 2nd column and have it printed in place of column 1. Remaining columns are needed as it.
test data:
ProbeSet GeneSymbol X22565285 X22566285
ILMN_1050008 MYOCD 6.577 7.395
ILMN_1050014 GPRC6A 6.595 6.668
ILMN_1050017 ... (2 Replies)
Discussion started by: genome
2 Replies
LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1)NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS --predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO bup-midx(1), bup-save(1)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-margin(1)