You need to determine what rounding rules you want to use for tie-breaking cases (see Wikipedia's discussion on rounding)
and you need to realize that even in double precision floating point, the result of a floating point calculation is not always exact (even when computing a value using decimal calculations would be exact). For example, the awk program (which uses double precision floating point for its calculations):
produces the output:
not the output you might expect:
Which shows two examples where decimal arithmetic produces exact results, but binary arithmetic produced one result that was a little bit high and one result that was a little bit low.
Hello again.
I'm trying to use BC to calculate some numbers in a shell script.
I want to have the numbers rounded off to 1 decimal place.
for example:
initsize=1566720
zipsize=4733
I'm trying to get the ratio between them. the equation is:
(($initsize-$zipsize)/$initsize)*100
so... (3 Replies)
Hi,
Can any one help me in finding a solution for rounding off to 2 decimal places.
I am using the following code:
VAR1=.01292105263157894736
VAR2=`echo "scale=2; $VAR1 * 100" | bc -l`
The result I 'm getting is
1.29210526315789473600
But I need the output as 1.29
Thanks
Shash (2 Replies)
Hello,
i have some variables say:
x=1.4
y=3.7
I wish to round off these values to :
x = 2 (after rounding off)
y = 4 (after rounding off)
I am stuck.
Please help. (7 Replies)
Hello,
I searched a lot on this Forum.
Please help me with the below problem.
I want to divide two numbers and the result should be the next nearest whole number.
E.G. Dividing 10.8/5 ideally gives 2.16. But the result should be 3 i.e. rounded off to the next whole number.
Any help will... (2 Replies)
I need some help with my rouding script. I have started pretty much from scratch and have no idea if its correct or even close but I have been trying and have gotten to this point. i keep getting syntax errors and im not sure what is wrong. Here is what I got
let value=$1;
while
do
let... (0 Replies)
I need some help with my rouding script. I have started pretty much from scratch and have no idea if its correct or even close but I have been trying and have gotten to this point. i keep getting syntax errors and im not sure what is wrong. Here is what I got
let value=$1;
while
do
let... (4 Replies)
Hi,
I am currently using tcsh
I am trying to round a decimal number to the ten-thousandths place
For instance:
1.23456 is rounded up towards 1.2346
I am not looking for truncation, but for rounding. Anyone know how to do this with awk or expr?
Thanks (2 Replies)
Dear Experts,
I'm trying to find a way to round a number but in this way:
14367.577 ---> 14000
I used the following to round the number to the closer integer:
echo $var|awk '{print int($1+0.5)}'
and also:
xargs printf "%1.0f"
However, they don't work for my above... (9 Replies)
Hi all of you,
Would be great if you help me with how to round up to whole number from my input values like
2.99996,2.17890,3.00002,-2.3456,-2.7890
o/p should be like 3,2,3,-2,-3
thnks in adv!!!!
regards (3 Replies)
How to round off a decimal number to higher whole number using ceil command in unix?
Eg. 4.41 or 4.11 or 4.51 should be rounded off to 5. (11 Replies)
Discussion started by: SanjayKumar28
11 Replies
LEARN ABOUT MOJAVE
lrint
RINT(3) BSD Library Functions Manual RINT(3)NAME
rint, lrint, llrint -- round to integral value
SYNOPSIS
#include <math.h>
double
rint(double x);
long double
rintl(long double x);
float
rintf(float x);
long int
lrint(double x);
long int
lrintl(long double x);
long int
lrintf(float x);
long long int
llrint(double x);
long long int
llrintl(long double x);
long long int
llrintf(float x);
DESCRIPTION
The rint() functions return the integral value nearest to x (according to the prevailing rounding mode) in floating-point format.
The lrint() and llrint() functions return the integral value nearest to x (according to the prevailing rounding mode) in the return formats
specified. If the rounded value is outside the range of the return type, the numeric result is unspecified and the "invalid" floating-point
exception is raised. A range error may occur if the magnitude of x is too large.
SPECIAL VALUES
rint(+-0) returns +-0 for all rounding modes.
rint(+-infinity) returns +-infinity for all rounding modes.
All these functions raise the "inexact" floating-point exception if the result differs in value from the argument (except when they raise
some other floating-point exception, such as "invalid").
NOTE
The rinttol() function is deprecated. Please use the C99 function lrint() instead.
SEE ALSO abs(3), fabs(3), ceil(3), floor(3), math(3)STANDARDS
The rint() , lrint() , and llrint() functions conform to ISO/IEC 9899:2011.
BSD July 02, 2008 BSD