How do I remove leading spaces in UNIX when count of space character is not fixed? Example below- Post: 302983863

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Top Forums UNIX for Beginners Questions & Answers How do I remove leading spaces in UNIX when count of space character is not fixed? Example below- Post 302983863 by RavinderSingh13 on Tuesday 18th of October 2016 03:43:20 AM

10-18-2016

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Quote:

Originally Posted by Tanu

Agree. Apologies for not providing proper requirement. Updated my original question.
This latest solution provided by you is not working as well. Error is "grep: write error: Broken pipe"
my piece of code is as below (nothing else in script except below calculation)-

Code:

my @pendJobs = `showStreamsGLIS$reg.$env.ksh  | awk '/OH|RU|OI/{sub(/^ +/,X,$0);print}'`;
chomp(@pendJobs);
print Dumper(\@pendJobs);
exit 1;

Hello Tanu,

So a important step of trouble shooting is either in any tool/code/operation is never neglect your error messages. So here we could see you script and then awkcommand is there, so it means there could be a chance your script itself is having issues, so following are the points:

Please try to run your script independently, is it running or not?
Post your script(if possible) or let us know what it does with complete details.
Check if you have used egrepcommand in script and try to figure out if that works or not?

Please follow above steps and additional too if you get any and let us know how it goes then.

Thanks,
R. Singh

Last edited by RavinderSingh13; 10-18-2016 at 06:31 AM.. Reason: Converted to formatted number-list with roman numerals

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LEARN ABOUT DEBIAN

bup-margin

bup-margin(1)						      General Commands Manual						     bup-margin(1)

NAME

       bup-margin - figure out your deduplication safety margin

SYNOPSIS

       bup margin [options...]

DESCRIPTION

       bup margin  iterates  through  all  objects  in	your  bup repository, calculating the largest number of prefix bits shared between any two
       entries.  This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.

       For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45.  That  means  a  46-bit
       hash  would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
       its first 46 bits.

       The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects.  Since SHA-1 hashes have 160 bits,
       that  leaves 115 bits of margin.  Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
       with far fewer objects.

       If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see	if
       you're getting dangerously close to 160 bits.

OPTIONS

       --predict
	      Guess  the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
	      from the guess.  This is potentially useful for tuning an interpolation search algorithm.

       --ignore-midx
	      don't use .midx files, use only .idx files.  This is only really useful when used with --predict.

EXAMPLE

	      $ bup margin
	      Reading indexes: 100.00% (1612581/1612581), done.
	      40
	      40 matching prefix bits
	      1.94 bits per doubling
	      120 bits (61.86 doublings) remaining
	      4.19338e+18 times larger is possible

	      Everyone on earth could have 625878182 data sets
	      like yours, all in one repository, and we would
	      expect 1 object collision.

	      $ bup margin --predict
	      PackIdxList: using 1 index.
	      Reading indexes: 100.00% (1612581/1612581), done.
	      915 of 1612581 (0.057%)

SEE ALSO

       bup-midx(1), bup-save(1)

BUP

       Part of the bup(1) suite.

AUTHORS

       Avery Pennarun <apenwarr@gmail.com>.

Bup unknown-															     bup-margin(1)

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