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Top Forums UNIX for Beginners Questions & Answers How do I remove leading spaces in UNIX when count of space character is not fixed? Example below- Post 302983857 by Tanu on Tuesday 18th of October 2016 02:33:59 AM
Old 10-18-2016
Question How do I remove leading spaces in UNIX when count of space character is not fixed? Example below-

Script showStreamsGLIS$reg.$env.ksh gives me output as below-

Code:
Job  Stime Etime Status ExitCode
      GLIS-AS-S-EFL-LOCK-B   -----                -----                OI 103313880/0
    GLIS-ALL-Q-EOD-FX-UPDT-1730-B -----                -----                TE 0/0
    GLIS-TK-S-BWSOD-B        -----                -----                OI 191344064/0
      GLIS-TK-S-BWSODWAIT-B  -----                -----                OI 191344064/0
GLIS-ALL-S-BWEC-B            10/06/2016  10:48:12 -----                RU 196982837/1
  GLIS-ALL-S-BWEC-START-B    10/06/2016  10:48:13 -----                RU 196982837/1
    GLIS-ALL-S-BWEC-GATHER   10/06/2016  10:48:16 -----                RU 196982837/1
    GLIS-ALL-S-BWEC-BWPP-BAL-J -----                -----                OI 134547446/0
    GLIS-ALL-S-BWEC-BWBM-BALS-J -----                -----                OI 134547446/0
GLIS-ALL-S-EOD-FX-UPDT-1730-B -----                -----                OI 0/0
     GLIS-ALL-R-EOD-FX-UPDT-1730-B -----                -----                ST 0/0
    GLIS-ALL-Q-EOD-FX-UPDT-1730-B -----                -----                TE 0/0

My requirement is to get rows containing status as 'OI/OH/RU' (highlighted few possible status values) and remove all trailing spaces. And I am trying to integrate this code in a perl script.

Idea is to do it without saving the output in a file.

Last edited by Tanu; 10-18-2016 at 04:28 AM..
 

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CUBRID_PREPARE(3)							 1							 CUBRID_PREPARE(3)

cubrid_prepare - Prepare a SQL statement for execution

SYNOPSIS
resource cubrid_prepare (resource $conn_identifier, string $prepare_stmt, [int $option]) DESCRIPTION
The cubrid_prepare(3) function is a sort of API which represents SQL statements compiled previously to a given connection handle. This pre-compiled SQL statement will be included in the cubrid_prepare(3). Accordingly, you can use this statement effectively to execute several times repeatedly or to process long data. Only a single statement can be used and a parameter may put a question mark (?) to appropriate area in the SQL statement. Add a parameter when you bind a value in the VALUES clause of INSERT statement or in the WHERE clause. Note that it is allowed to bind a value to a MARK(?) by using the cubrid_bind(3) function only. PARAMETERS
o $conn_identifier -Connection identifier. o $prepare_stmt -Prepare query. o $option -OID return option CUBRID_INCLUDE_OID. RETURN VALUES
Request identifier, if process is successful; FALSE, if process is unsuccessful. EXAMPLES
Example #1 cubrid_prepare(3) example <?php $conn = cubrid_connect("localhost", 33000, "demodb"); $sql = <<<EOD SELECT g.event_code, e.name FROM game g JOIN event e ON g.event_code=e.code WHERE host_year = ? AND event_code NOT IN (SELECT event_code FROM game WHERE host_year=?) GROUP BY event_code; EOD; $req = cubrid_prepare($conn, $sql); cubrid_bind($req, 1, 2004); cubrid_bind($req, 2, 2000); cubrid_execute($req); $row_num = cubrid_num_rows($req); printf("There are %d event that exits in 2004 olympic but not in 2000. For example: ", $row_num); printf("%-15s %s ", "Event_code", "Event_name"); printf("---------------------------- "); $row = cubrid_fetch_assoc($req); printf("%-15d %s ", $row["event_code"], $row["name"]); $row = cubrid_fetch_assoc($req); printf("%-15d %s ", $row["event_code"], $row["name"]); cubrid_disconnect($conn); ?> The above example will output: There are 27 event that exits in 2004 olympic but not in 2000. For example: Event_code Event_name ---------------------------- 20063 +91kg 20070 64kg SEE ALSO
cubrid_execute(3), cubrid_bind(3). PHP Documentation Group CUBRID_PREPARE(3)
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