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insert leading zeroes based on the character count


 
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# 1  
Old 10-30-2009
insert leading zeroes based on the character count

Hi,

I need add leading zeroes to a field in a file based on the character count. The field can be of 1 character to 6 character length. I need to make the field 14bytes.

eg:
8351,20,1
8351,234,6
8351,2,0
8351,1234,2
8351,123456,1
8351,12345,2

This should become.

8351,00000000000020,1
8351,00000000000234,6
8351,00000000000002,0
8351,00000000001234,2
8351,00000000123456,1
8351,00000000012345,2

Any help will be much appreciated.
# 2  
Old 10-30-2009
Try this:

Code:
awk -F, '{$2=sprintf("%014d",$2)}1' OFS="," file

# 3  
Old 10-30-2009
Code:
  awk 'BEGIN { FS = ","; OFS = "," }; {$2=sprintf("%014d",$2)}1' filename

damn, you beat me...

Last edited by mkastin; 10-30-2009 at 02:10 PM..
# 4  
Old 11-02-2009
Thanks guys. It worked Smilie

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