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Top Forums Shell Programming and Scripting Help understanding the script Post 302983522 by hasn318 on Wednesday 12th of October 2016 04:54:14 PM
Old 10-12-2016
Help understanding the script

Could someone please help me in understanding the code below:
Code:
#!/usr/bin/ksh
Month=`date|cut -c5-7`                         
Day=`date|cut -c9-10`                          
Year=`date|cut -c27-28`
Rom2Jul() { case $Month in Feb) Day=$(( $Day+31 ));;
                           Mar) Day=$(( $Day+59 ));;
                           Apr) Day=$(( $Day+90 ));;
                           May) Day=$(( $Day+120 ));;
                           Jun) Day=$(( $Day+151 ));;
                           Jul) Day=$(( $Day+181 ));;
                           Aug) Day=$(( $Day+212 ));;
                           Sep) Day=$(( $Day+243 ));;
                           Oct) Day=$(( $Day+273 ));;
                           Nov) Day=$(( $Day+304 ));;
                           Dec) Day=$(( $Day+334 ));; esac }
Rom2Jul

Current=$(( $Year*365+$Day-2 ))

PrevHostname=''
PrevBackup=0
while read input                               
do Month=${input:0:3}
   Day=${input:4:2}
   Hostname=${input:13:12}
   Rom2Jul
   if [[ ${input:9:1} = ':' ]] then Year=`date|cut -c27-28`; else Year=${input:10:2}; fi
   Backup=$(( $Year*365+$Day ))
   if [[ $PrevHostname = '' ]] then PrevHostname=$Hostname; PrevBackup=$Backup
      else if [[ $PrevHostname != $Hostname ]] then echo $PrevBackup $PrevHostname 
                                                    PrevHostname=$Hostname; PrevBackup=$Backup
              else if (( $Backup > $PrevBackup )) then PrevBackup=$Backup; fi; fi; fi; done 
echo $PrevBackup $PrevHostname

---------- Post updated at 04:54 PM ---------- Previous update was at 04:35 PM ----------

I am specifically trying to understand the
Code:
PrevHostname=''
PrevBackup=0
while read input                               
do Month=${input:0:3}
   Day=${input:4:2}
   Hostname=${input:13:12}

 

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PAPS(1) 						      General Commands Manual							   PAPS(1)

NAME
paps - UTF-8 to PostScript converter using Pango SYNOPSIS
paps [options] files... DESCRIPTION
paps reads a UTF-8 encoded file and generates a PostScript language rendering of the file. The rendering is done by creating outline curves through the pango ft2 backend. OPTIONS
These programs follow the usual GNU command line syntax, with long options starting with two dashes (`-'). A summary of options is included below. --landscape Landscape output. Default is portrait. --columns=cl Number of columns output. Default is 1. Please notice this option isn't related to the terminal length as in a "80 culums terminal". --font=desc Set the font description. Default is Monospace 12. --rtl Do right to left (RTL) layout. --paper ps Choose paper size. Known paper sizes are legal, letter and A4. Default is A4. Postscript points Each postscript point equals to 1/72 of an inch. 36 points are 1/2 of an inch. --bottom-margin=bm Set bottom margin. Default is 36 postscript points. --top-margin=tm Set top margin. Default is 36 postscript points. --left-margin=lm Set left margin. Default is 36 postscript points. --right-margin=rm Set right margin. Default is 36 postscript points. --gutter-width=gw Set gutter width. Default is 40 postscript points. --help Show summary of options. --header Draw page header for each page. --markup Interpret the text as pango markup. --lpi Set the lines per inch. This determines the line spacing. --cpi Set the characters per inch. This is an alternative method of specifying the font size. --stretch-chars Indicates that characters should be stretched in the y-direction to fill up their vertical space. This is similar to the texttops behaviour. AUTHOR
paps was written by Dov Grobgeld <dov.grobgeld@gmail.com>. This manual page was written by Lior Kaplan <kaplan@debian.org>, for the Debian project (but may be used by others). April 17, 2006 PAPS(1)
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