Hoping someone can help with something I'm sure is an easy fix. I'm trying to setup a cron to ssh to a server and check if a process is running. I've got keys setup from the jumpbox which I'm originating the check from (I don't have root privileges), when running the check manually from the just box it has no issue logging works perfectly however when logging in during the cron process it fails. It keeps prompting with the below
I'm just using the standard ssh login string in the cron
Could anyone advise if they have any expierence with this. I mean i know the keys work as its fine when doing it from my shell.
Thanks
Last edited by rbatte1; 10-10-2016 at 11:06 AM..
Reason: Spelling corrections
Hi,
Does anyone know why the cron job fail to run automatically ?
We have the problem with some Solaris 2.5.1 Machine !
The cron seemd to fail to submit the jobs defined at the defined time !!
Why ?
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We are very sure the problem is due to... (6 Replies)
how to use the arrow keys in shell scripting. is there any special synatax / command for this.
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replies appreciated
raguram R (3 Replies)
I have ssh setup on 2 boxes ( aix / linux ).
building a batchjob i have made a plaintext key.
I force the command in the authorized_keys file
running from aix -> linux
ssh -i ~/.ssh/batchkey user@remote works perfect
but from linux -> aix
it get the following
debug1:... (1 Reply)
Hi,
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Hi
Am having 2 files.
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If
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Hi All,
I am having knowledge on some basics of ssh and wanted to know what are the public keys and how can we create and implement it in connecting server.
Please provide the information for the above, it would be helpful for me.
Thanks,
Ravindra (1 Reply)
Hello,
I am stuck... i dunno why does my test fail... any idea ?
#!/bin/bash
dos2unix info.txt
Distor=Distributeur
LINE=$(cat info.txt | sed -n 1p)
echo $LINE
echo $Distor
echo ""
echo "123-$LINE-123"
echo "123-$Distor-123"
if ; then
LINE2=$(cat info.txt | sed -n 2p)
echo $Distor... (14 Replies)
Hello gurus,
I am making what I think is a simple db2 call from within a shell script but I am having difficulty producing the desired
report when I run the script shown below from a shell script in cron. For example, my script and the crontab file setup
is shown below:
#!/bin/ksh
db2... (3 Replies)
Discussion started by: okonita
3 Replies
LEARN ABOUT PLAN9
cron
CRON(8) System Manager's Manual CRON(8)NAME
cron - clock daemon
SYNOPSIS
auth/cron [-c]
DESCRIPTION
Cron executes commands at specified dates and times according to instructions in the files /cron/user/cron. It runs only on an authentica-
tion server. Option -c causes cron to create /cron/user and /cron/user/cron for the current user; it can be run from any Plan 9 machine.
Blank lines and lines beginning with # in these files are ignored. Entries are lines with fields
minute hour day month weekday host command
Command is a string, which may contain spaces, that is passed to an rc(1) running on host for execution. The first five fields are integer
patterns for
minute 0-59
hour 0-23
day of month 1-31
month of year 1-12
day of week 0-6; 0=Sunday
The syntax for these patterns is
time : '*'
| range
range : number
| number '-' number
| range ',' range
Each number must be in the appropriate range. Hyphens specify inclusive ranges of valid times; commas specify lists of valid time ranges.
To run the job, cron calls host and authenticates remote execution, equivalent to running rx host command (see con(1)). The user's profile
is run with $service set to rx.
Cron is not a reliable service. It skips commands if it cannot reach host within two minutes, or if the cron daemon is not running at the
appropriate time.
EXAMPLES
Here is the job that mails system news.
% cat /cron/upas/cron
# send system news
15 8-17, 21 *** helix /mail/lib/mailnews
%
SOURCE
/sys/src/cmd/auth/cron.c
SEE ALSO con(1), rc(1)CRON(8)