This works, as in it will add and subtract as requested. However, AWK is removing the starting digit 0 on the output. I need to keep this as my script is adding and subtracting time.
The two issues I am facing is AWK removing the starting 0 and also if I add '1' to the "time" 1159 my way of counting time will output 1160, where as I would like it to read 1200.
Any help would be met would the greatest of appreciation.
Thank you
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Last edited by pshields1984; 09-01-2016 at 08:36 AM..
Reason: Changed QUOTE to CODE tags.
how can we add or subtract days from the output of date command in unix...
like if i want to subtract a day from the result of date command like this..
v_date=`date +%Y%m%d`
this wud give me 20080519
now i want to subtract one day from this.. so tht it wud give me 20080518..
how do i do... (1 Reply)
Hi All,
I have a file of 100 lines of each having 1000 columns. I need to find the difference of each column against each other. That means, Col1-Col1; Col1-Col2; Col1-Col3;......Col1-Col1000; Col2-Col1; Col2-Col2; Col2-Col3;.... and so on ....up to Col1000-Col1000.
Lets say the file is... (6 Replies)
Hi,
I'm writing an batch file to create report
In the batch file iam passing two arguments:startdate and finishdate
Ex: startdate=07-sep-2009 finishdate=07-sep-2011
I need to have script that takes command line argument as input and gives me out currentdate last year and current date... (2 Replies)
ok, so i have a bunch of numbers in a file that i'd like to add up.
i dont know how to do it.
This is how far i've gotten:
echo "4 4 5 4 3 4 3 3 4 2 43 3 293 49 23" | sed 's/ / + /g' | awk -F" "
I dont want to use the expr command with this as i dont trust it. any advice?
thanks (1 Reply)
Hi Gurus!
I have a static date in a YYYYMMDD format; and I want get the date 2 years in the past and 2 years in the future.
static_date=20010203
old_date=$static_date - 3 years
future_date=$static_date + 2 years
I was only able to research on dates that are current and not on static... (3 Replies)
Hi everyone, I had a similar question a couple days ago but my problem has gotten significantly (to me anyway) more complex.
I have two files:
File 1:
0808 166 166 62 9 0
1000fights 1 1 2 1 0
100places2visit 2 2 2 2 0
10veronica91 167 167 3 1 0
11thgorgeous 346 346 3806 1461 122... (2 Replies)
Hi again. Sorry for all the questions — I've tried to do all this myself but I'm just not good enough yet, and the help I've received so far from bartus11 has been absolutely invaluable. Hopefully this will be the last bit of file manipulation I need to do.
I have a file which is formatted as... (4 Replies)
Discussion started by: crunchgargoyle
4 Replies
LEARN ABOUT OSX
colrm
COLRM(1) BSD General Commands Manual COLRM(1)NAME
colrm -- remove columns from a file
SYNOPSIS
colrm [start [stop]]
DESCRIPTION
The colrm utility removes selected columns from the lines of a file. A column is defined as a single character in a line. Input is read
from the standard input. Output is written to the standard output.
If only the start column is specified, columns numbered less than the start column will be written. If both start and stop columns are spec-
ified, columns numbered less than the start column or greater than the stop column will be written. Column numbering starts with one, not
zero.
Tab characters increment the column count to the next multiple of eight. Backspace characters decrement the column count by one.
ENVIRONMENT
The LANG, LC_ALL and LC_CTYPE environment variables affect the execution of colrm as described in environ(7).
EXIT STATUS
The colrm utility exits 0 on success, and >0 if an error occurs.
SEE ALSO awk(1), column(1), cut(1), paste(1)HISTORY
The colrm command appeared in 3.0BSD.
BSD August 4, 2004 BSD
09-01-2016
