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Top Forums Shell Programming and Scripting sed random \n for "n" range of character occurrences Post 302977627 by RudiC on Wednesday 20th of July 2016 03:42:57 PM
Old 07-20-2016
I'm not aware of a random function in sed; which version do you use?

And, while your code sample (ignoring the RANDOM stuff) will add a <NL> char to some EOL (end of line), in post#1 you specify that dots should be replaced. Do I guess correctly that dots are not necessarily at EOLs?

Would a non-sed solution be acceptable?
 

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GREP(1) 						      General Commands Manual							   GREP(1)

NAME
grep - search a file for lines containing a given pattern SYNOPSIS
grep [-elnsv] pattern [file] ... OPTIONS
-e -e pattern is the same as pattern -c Print a count of lines matched -i Ignore case -l Print file names, no lines -n Print line numbers -s Status only, no printed output -v Select lines that do not match EXAMPLES
grep mouse file # Find lines in file containing mouse grep [0-9] file # Print lines containing a digit DESCRIPTION
Grep searches one or more files (by default, stdin) and selects out all the lines that match the pattern. All the regular expressions accepted by ed and mined are allowed. In addition, + can be used instead of * to mean 1 or more occurrences, ? can be used to mean 0 or 1 occurrences, and | can be used between two regular expressions to mean either one of them. Parentheses can be used for grouping. If a match is found, exit status 0 is returned. If no match is found, exit status 1 is returned. If an error is detected, exit status 2 is returned. SEE ALSO
cgrep(1), fgrep(1), sed(1), awk(9). GREP(1)
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