awk script: need help Post: 302977260

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Unable to pass shell script parameter value to awk command in side the same script

Variable I have in my shell script diff=$1$2.diff id=$2 new=new_$diff echo "My id is $1" echo "I want to sync for user account $id" ##awk command I am using is as below cat $diff | awk -F'~' ''$2 == "$id"' {print $0}' > $new I could see value of $id is not passing to the awk...

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Passing shell script parameter value to awk command in side the script

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tzselect

TZSELECT(8)						      System Manager's Manual						       TZSELECT(8)

NAME

       tzselect - select a time zone

SYNOPSIS

       tzselect

DESCRIPTION

       The  tzselect program asks the user for information about the current location, and outputs the resulting time zone description to standard
       output.	The output is suitable as a value for the TZ environment variable.

       All interaction with the user is done via standard input and standard error.

ENVIRONMENT VARIABLES

       AWK    Name of a Posix-compliant awk program (default: awk).

       TZDIR  Name of the directory containing time zone data files (default: /usr/local/etc/zoneinfo).

FILES

       TZDIR/iso3166.tab
	      Table of ISO 3166 2-letter country codes and country names.

       TZDIR/zone.tab
	      Table of country codes, latitude and longitude, TZ values, and descriptive comments.

       TZDIR/TZ
	      Time zone data file for time zone TZ.

EXIT STATUS

       The exit status is zero if a time zone was successfully obtained from the user, nonzero otherwise.

SEE ALSO

       newctime(3), tzfile(5), zdump(8), zic(8)

																       TZSELECT(8)

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