Compare 2 Strings Post: 302976680

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Top Forums Shell Programming and Scripting Compare 2 Strings Post 302976680 by aderamos12 on Sunday 3rd of July 2016 10:37:51 PM

07-03-2016

Registered User

Compare 2 Strings

I have 2 values V_1_4_4_b1 and V_1_5_1_RC_b1. I would need to compare them and determine if the 1st value is greater, less or equal
than the 2nd value. The result should need to have a return value.
I have below code in bash function but it seems it is not comparing it correctly. Any help will be greatly appreciated. Thanks.

Code:

 checkversion ()
{
  local mod="$1"
  local vers="$2"
  local slink="/app/mes_dwh/$mod/${mod}"
  local target1="$(readlink "$slink" | cut -d 'V' -f2)"
  local addstring="V"
  local target="$addstring$target1"
   case "$target" in
        V_[0-9]_[0-9]_[0-9]_RC_b* | \
        V_[0-9]_[0-9]_[0-9]_b* ) ;;
        *) fail "bad version string: '$target'";;
  esac
  
  #compare major version
  local old="$( echo "$target" | cut -d_ -f2 )"
  local new="$( echo "$vers" | cut -d_ -f2 )"
  test "$old" -gt "$new" && return 77
   #compare middle version
  old="$( echo "$target" | cut -d_ -f3 )"
  new="$( echo "$vers" | cut -d_ -f3 )"
  test "$old" -gt "$new" && return 77
   #compare minor version
  old="$( echo "$target" | cut -d_ -f4 )"
  new="$( echo "$vers" | cut -d_ -f4 )"
  test "$old" -gt "$new" && return 77
   #compare build version
  old="$( echo "$target" | cut -d_ -f5 )"
  new="$( echo "$vers" | cut -d_ -f5 )" 
 
  case "${old}_${new}" in
  b*_RC) return 77;;
  b*_b*)
     #compare build level of final version (with 'b' stripped off
     old="${old#b}"
     new="${new#b}"
     test "$old" -gt "$new"  && return 77
     ;;
  RC_RC)
     #compare level of RC version (with the 'b' stripped off)
    old="$( echo "$target" | cut -d_ -f6 | cut -c2- )"
    new="$(echo "$vers" | cut -d_ -f6 | cut -c2-)"
    test "$old" -gt "$new" && return 77
    ;;
  RC_b*) return 0;;
  *) fail "unrecognized pattern";;
  esac
  
   return 0
 }

aderamos12

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