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Full Discussion: How to get front and back parameter of each characters?
Top Forums Shell Programming and Scripting How to get front and back parameter of each characters? Post 302974159 by RavinderSingh13 on Thursday 26th of May 2016 03:00:19 AM
Old 05-26-2016
Quote:
Originally Posted by paranrat
In this case the word is "hello"

Code:
                        h
                        e
h e l l o   - - ->      l 
                        l
                        o

focus on "h" ; before character h is null and assign with '#". After character h are "e" and "l".
focus on "e" ; before character e is "h". After character e are "l" and "l".
focus on "l" ; before character l are "h" and "e". After character l are "l" and "o".
focus on "l" ; before character l are "e" and "l". After character l is "o".
focus on "o" ; before character o are "l" and "l". After character o is null and assign with '#".

I would like to get 2 characters before and after of that focused on. I expect to get like below:

Code:
# # h e l  // 2 characters before h are "#" and "#". 2 characters after h are "e" and "l"
# h e l l  // 2 characters before e are "#" and "h". 2 characters after e are "l" and "l"
h e l l o  // 2 characters before l are "h" and "e". 2 characters after l are "l" and "o" 
e l l o #  // 2 characters before l are "e" and "l". 2 characters after l are "o" and "#"
l l o # #  // 2 characters before o are "l" and "l". 2 characters after o are "#" and "#"

Hello paranrat,

Could you please try following and let me know if this helps.
Code:
echo "h e l l o" | awk '{num=split($0, A," ");for(i=1;i<=num;i++){if(i==1){print "# #" OFS A[i] OFS A[i+1] OFS A[i+2]} else if(i==num){print A[i-2] OFS A[i-1] OFS A[i] OFS "# #"} else {Q=A[i-2] OFS A[i-1] OFS A[i] OFS A[i+1] OFS A[i+2];sub(/^[[:space:]]+/,"# ",Q);sub(/[[:space:]]+$/," #",Q);print Q}}}'

Output will be as follows.
Code:
# # h e l
# h e l l
h e l l o
e l l o #
l l o # #

Thanks,
R. Singh
This User Gave Thanks to RavinderSingh13 For This Post:
paranrat
 

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