Hi,
I just wandering how to split a record which has more than one delimiter,
i have a file which contains pattern as group separtor and ~ as field separtor, Ultimately I need consider even the groups as a field, So i need to make this multi-delimited file into ~ delimited file.
My record... (4 Replies)
hi, pls someone tell me how to extract delimiters from any file and pass it to a unix script.since, im a beginner in unix i find it little bit difficult.how to use awk to do this? (9 Replies)
Hi
I have a file in which delimiter is ';'
However if the delimiter is within "" it is a part of the string and not delimiter.
How to get the fields ? I want to replace the delimiter ';' to '|'.
The file contains data like this :
11111; “2222 2222”; “3333; 3333”; “4444 ""44444”
The file... (2 Replies)
Hello,
I am trying to find the record count in a specific folder,
Here is the part of the code
===========================
STARTDATE=`date +"%y%m%d%H%M"`
for i in `ls *.DAT`
do
wc -l $i >> /XYZ/SrcFiles/"Record_counts"$STARTDATE.csv
... (2 Replies)
Hi All,
I woul like to know with out opening a file in unix ,how we can find out what is the delemeter in that file...
Thanks..
edit by bakunin: changed thread title to "delimiter" so it can be found. (4 Replies)
Hi there,
I am with this one column input text file to change layout, please help. Thanks. I have awk, sed.
$ cat input
Median
1.0
2.3
3.0
Median
35.0
26.3
45.7
10.1
63.1
Median
1.2
2.3 (8 Replies)
Hi,
I have a No Delimiter variable length text file with following schema -
Column Name Data length
Firstname 5
Lastname 5
age 3
phoneno1 10
phoneno2 10
phoneno3 10
sample data - ... (16 Replies)
Hi,
I have a input
/dev/cm/test1.txt
/qa/tm/hmkr/cc/test2.txt
and I need an out like below
foldername, filename
/dev/cm/,test1.txt
/qa/tm/hmkr/cc/,test2.txt
I tried with awk $NF, but I'm getting the filenames and not folder names. Please let me know how to achive the above... (5 Replies)
Hi,
Extremely new to Perl scripting, but need a quick fix without using TEXT::CSV
I need to read in a file, pass any delimiter as an argument, and convert it to bar delimited on the output. In addition, enclose fields within double quotes in case of any embedded delimiters.
Any help would... (2 Replies)
Discussion started by: JPB1977
2 Replies
LEARN ABOUT MINIX
cut
CUT(1) General Commands Manual CUT(1)NAME
cut - select out columns of a file
SYNOPSIS
cut [ -b | -c] list [file...]
cut -f list [-d delim] [ -s]
OPTIONS -b Cut specified bytes
-c Select out specific characters
-d Change the column delimiter to delim
-f Select out specific fields that are separated by the
-i Runs of delimiters count as one
-s Suppres lines with no delimiter characters, when used
EXAMPLES
cut -f 2 file # Extract field 2
cut -c 1-2,5 file # Extract character columns 1, 2, and 5
cut -c 1-5,7- file # Extract all columns except 6
DESCRIPTION
[file...]" delimiter character ( see delim)" with the -f option. Lines with no delimiters are passwd through untouched"
Cut extracts one or more fields or columns from a file and writes them on standard output. If the -f flag is used, the fields are sepa-
rated by a delimiter character, normally a tab, but can be changed using the -d flag. If the -c flag is used, specific columns can be
specified. The list can be comma or BLANK separated. The -f and -c flags are mutually exclusive. Note: The POSIX1003.2 standard requires
the option -b to cut out specific bytes in a file. It is intended for systems with multi byte characters (e.g. kanji), since MINIX uses
only one byte characters, this option is equivalent to -c. For the same reason, the option -n has no effect and is not listed in this man-
ual page.
SEE ALSO sed(1), awk(9).
CUT(1)