Sponsored Content
Full Discussion: sed match
Top Forums Shell Programming and Scripting sed match Post 302972500 by Don Cragun on Friday 6th of May 2016 05:01:42 AM
Old 05-06-2016
Quote:
Originally Posted by andy391791
Hi , thanks for your replies.

Both commands work, and i understand fully the code

Code:
sed 's/.*\(-.*-\).*/\1/'

Please ignore this post. I obviously needed to get some sleep before I posted it.

OK. I know that you already understand it, but just to be clear, the \1 in the replacement string expands to the text that was matched between the 1st \( and the matching \) in the substitute regular expression. And, the -.*- between the parens in that RE will match the 1st - on the line (- in the RE), everything after the 1st - unto but not including the last - on the line (.* in the RE), and the last - on the line (- in the RE).
Quote:
However i don't really understand how this works:
Code:
sed 's/.*\(-[^-]*-\).*/\1/'

To me it seems like its trying to match - then anything beginning with - followed by - . I know im wrong, are you able to explain how it works?

Also , what is the best way if i wanted to not have the - ie with an output of just

010516 and 050516

Many thanks
The RE between parentheses in this sed substitute command (-[^-]*-) matches the 1st - on the line (- in the RE), the longest string of characters available that does not include a - ([^-]* in the RE), and the 2nd - on the line (- in the RE).

So, these sed commands do the same thing for input lines that contain two or fewer - characters. But, for lines that have three or more - characters, the 1st sed prints the 1st and last - and everything between them while the 2nd sed command prints the 1st and 2nd - and everything between them. And, to stop printing the matched - characters, move them outside the parentheses in the RE:
Code:
sed 's/.*-\(.*\)-.*/\1/'
sed 's/.*-\([^-]*\)-.*/\1/'

Please ignore this post. I obviously needed to get some sleep before I posted it.

Last edited by Don Cragun; 05-06-2016 at 05:02 PM.. Reason: Incomplete and mostly wrong discussion.
This User Gave Thanks to Don Cragun For This Post:
 

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

How can I match . (actual dot) using sed?

Hi All, How can I match . (actual dot) using sed? Please help. Thanks (9 Replies)
Discussion started by: jingi1234
9 Replies

2. Shell Programming and Scripting

how do I negate a sed match

I have a text file that has links in it. I can write a match for sed to replace the link with anything. For example: http://www.google.com becomes XxX But what I'm after is not to replace the link with something but to remove everything else and just leave the link. I want a... (5 Replies)
Discussion started by: muxman
5 Replies

3. Shell Programming and Scripting

Multiple line match using sed

Please help! Input pattern, where ... could be any number of lines struct A { Blah1 Blah2 Blah3 ... } B; output pattern struct AB { Blah1 Blah2 Blah3 ... }; I need help in extracting everything between { and } if it would have been on a single line { \(.*\)} should have worked. (15 Replies)
Discussion started by: SiftinDotCom
15 Replies

4. UNIX for Dummies Questions & Answers

sed can't match '\n' ?!

Hi: it seems very strange. there is a file with multiple lines. After I squeezed out the consecutive blank lines (and some other text processing), somehow the sed '/\n/! d' file can not generate any output, as if it can't find any line with newline. the file is has many lines, so... (9 Replies)
Discussion started by: phil518
9 Replies

5. Shell Programming and Scripting

Sed Pattern Match

Hi, I would like to use SED to do the following string replacement: asd1abc to www1cda asd2abc to www2cda ... asd9abc to www9cda I can use 'asd.abc' to find the orignal string, however I don't know how to generate the target string. Any suggestion? Thanks, ... (2 Replies)
Discussion started by: mail4mz
2 Replies

6. Shell Programming and Scripting

Use of sed to find everything after first match!

Hi Guys So far I have got this to work: set x = temp1:temp2:temp3 echo $x | sed 's/.*:\(.*\).*/\1/' Answer: temp3 But I want answer as temp2:temp3, that is everything after the first ":" is found. If anybody can help with a bit of description that will be great. Thanks in Advance (1 Reply)
Discussion started by: dixits
1 Replies

7. Shell Programming and Scripting

Exact match using sed

I would like replace all the rows in a file if a row has an exact match to number say 21 in a tab delimited file. I want to delete the row only if it has 21 any of the rows but it should not delecte the row that has 542178 or 563421. I tried this sed '/\<21\>/d' ./inputfile > output.txt ... (7 Replies)
Discussion started by: Kanja
7 Replies

8. Shell Programming and Scripting

sed match exactly and delete

I am using following sed rule to delete 2 lines after a pattern match inclusive. # cat /tmp/temp.txt dns.com 11 22 mydns.com 11 22 dns.com.au 11 22 LAST LINE # cat /tmp/temp.txt | sed -e '/dns.com/,+2d' LAST LINE I just need to remove lines below dns.com only and NOT below... (5 Replies)
Discussion started by: anil510
5 Replies

9. Shell Programming and Scripting

sed print from last occurrence match until the end of last occurrence match

Hi, i have file file.txt with data like: START 03:11:30 a 03:11:40 b END START 03:13:30 eee 03:13:35 fff END jjjjjjjjjjjjjjjjjjjjj START 03:14:30 eee 03:15:30 fff END ggggggggggg iiiiiiiiiiiiiiiiiiiiiiiii I want the below output START (13 Replies)
Discussion started by: Jyotshna
13 Replies

10. Shell Programming and Scripting

Getting out of sed on first NOT match

i have a large file where i want to look for any record that is is larger or smaller than 21 and if it is the case i want to report and break SED .. how can i achieve it ? i dont want sed to scan the complete file after one non match is found. (4 Replies)
Discussion started by: boncuk
4 Replies
All times are GMT -4. The time now is 08:34 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy