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Top Forums Shell Programming and Scripting An interpolation between two files Post 302969836 by RudiC on Tuesday 29th of March 2016 04:27:29 AM
Old 03-29-2016
You didn't answer the question for the source of the voltages so a generic proposal was impossible.
Your solution may work for exactly 0.78 V and 0.945 V but no other input, so it may be not too valueable.
Why did you define the "time" variable? Why the "V" array?
 

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CGESV(l)								 )								  CGESV(l)

NAME
CGESV - compute the solution to a complex system of linear equations A * X = B, SYNOPSIS
SUBROUTINE CGESV( N, NRHS, A, LDA, IPIV, B, LDB, INFO ) INTEGER INFO, LDA, LDB, N, NRHS INTEGER IPIV( * ) COMPLEX A( LDA, * ), B( LDB, * ) PURPOSE
CGESV computes the solution to a complex system of linear equations A * X = B, where A is an N-by-N matrix and X and B are N-by-NRHS matri- ces. The LU decomposition with partial pivoting and row interchanges is used to factor A as A = P * L * U, where P is a permutation matrix, L is unit lower triangular, and U is upper triangular. The factored form of A is then used to solve the system of equations A * X = B. ARGUMENTS
N (input) INTEGER The number of linear equations, i.e., the order of the matrix A. N >= 0. NRHS (input) INTEGER The number of right hand sides, i.e., the number of columns of the matrix B. NRHS >= 0. A (input/output) COMPLEX array, dimension (LDA,N) On entry, the N-by-N coefficient matrix A. On exit, the factors L and U from the factorization A = P*L*U; the unit diagonal ele- ments of L are not stored. LDA (input) INTEGER The leading dimension of the array A. LDA >= max(1,N). IPIV (output) INTEGER array, dimension (N) The pivot indices that define the permutation matrix P; row i of the matrix was interchanged with row IPIV(i). B (input/output) COMPLEX array, dimension (LDB,NRHS) On entry, the N-by-NRHS matrix of right hand side matrix B. On exit, if INFO = 0, the N-by-NRHS solution matrix X. LDB (input) INTEGER The leading dimension of the array B. LDB >= max(1,N). INFO (output) INTEGER = 0: successful exit < 0: if INFO = -i, the i-th argument had an illegal value > 0: if INFO = i, U(i,i) is exactly zero. The factorization has been completed, but the factor U is exactly singular, so the solution could not be computed. LAPACK version 3.0 15 June 2000 CGESV(l)
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