Hi All,
My Input file looks like below:
Input:
100,200,300
$fw=`head -1 test.csv | awk -F, '{print \$1}'`;
$fw="'$fw"
$fw="$fw'"
print $fw
Output:'100'
I want the first field to be printed in single quotes ('') like above.
I could get the ouptput but the problem is single... (6 Replies)
Hello all,
Here is what my bash script does: sums number columns, saves the tot in new column, outputs if tot >= threshold val:
> cat getnon0file.sh
#!/bin/bash
this="getnon0file.sh"
USAGE=$this"
InFile="xyz.38"
Min="0.05"
#
awk '{sum=0; for(n=2; n<=NF; n++){sum+=$n};... (4 Replies)
Hello experts
I want to execute a awk command, which reads from txt files and sums the numbers from the first column for those listed only inside a <init> block -- The awk command is like
awk '/<\/?init>/{x = !x}x{a++}x && a > 2{sum+=$1}END{printf"%E" "\n", sum}
So, I want to execute... (2 Replies)
i have two files as shown below
t1.txt:
argument1
argu2
argu37
t2.txt:
22
33
44
i want o/p as
argument1 22
argu2 33
argu37 44
i am trying to merge two file under perl script using following
system("paste t1.txt t2.txt | awk... (3 Replies)
Hi,
I have an array with following data. First field shows the owner and second is unique name. Now i have to pic the latest value with respect to the date in case of duplicate.
like "def" is from two owners "rahul/vineet", now i want the latest from the two and the owner name also for all the... (9 Replies)
Hi Guys,
Hope everyone is fine :)
I have this code below:
#!/usr/bin/perl
$num_of_files=`ls | grep -v remover | wc -l`;
$remover=`ls -lrt | grep -v total | grep -v remover | head -1 | awk '{print $8}' | rm \`xargs\``;
if ($num_of_files>3) {
system ($remover);
}
When I... (3 Replies)
Hi all;
I have a Perl script that uses this awk command wrapped in a "system" call; it works exactly as I want it; however I want to keep this a Perl script and have very few if any "system" command...so the question; can someone help me code this in Perl please ... i have tried an now I am... (1 Reply)
Hi
I know sed and awk has options to give range of line numbers, but
I need to replace pattern in specific lines
Something like
sed -e '1s,14s,26s/pattern/new pattern/' file name
Can somebody help me in this....
I am fine with see/awk/perl
Thank you in advance (9 Replies)
Discussion started by: dani777
9 Replies
LEARN ABOUT MOJAVE
english5.18
English(3pm) Perl Programmers Reference Guide English(3pm)NAME
English - use nice English (or awk) names for ugly punctuation variables
SYNOPSIS
use English;
use English qw( -no_match_vars ) ; # Avoids regex performance penalty
# in perl 5.16 and earlier
...
if ($ERRNO =~ /denied/) { ... }
DESCRIPTION
This module provides aliases for the built-in variables whose names no one seems to like to read. Variables with side-effects which get
triggered just by accessing them (like $0) will still be affected.
For those variables that have an awk version, both long and short English alternatives are provided. For example, the $/ variable can be
referred to either $RS or $INPUT_RECORD_SEPARATOR if you are using the English module.
See perlvar for a complete list of these.
PERFORMANCE
NOTE: This was fixed in perl 5.20. Mentioning these three variables no longer makes a speed difference. This section still applies if
your code is to run on perl 5.18 or earlier.
This module can provoke sizeable inefficiencies for regular expressions, due to unfortunate implementation details. If performance matters
in your application and you don't need $PREMATCH, $MATCH, or $POSTMATCH, try doing
use English qw( -no_match_vars ) ;
. It is especially important to do this in modules to avoid penalizing all applications which use them.
perl v5.18.2 2014-01-06 English(3pm)