02-24-2016
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1. Shell Programming and Scripting
Hi Guys,
I am trying to reading in comma seperated values in awk. I can set the delimiter to be a comma, but the tricky part is that commas that appear within quotes are not to be considered as delimiters. Could someone please help.
Regards,
Laud (1 Reply)
Discussion started by: Laud12345
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2. UNIX for Dummies Questions & Answers
Hi All,
I am facing a problem while getting the data from an Oracle table
Problem:
I am getting rows from an Oracle table to a tab seperated file.
One of the columns in that table have value with in between spaces like
AAAAA AAA
It's loading fine to .tab file.
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3. Shell Programming and Scripting
Hi,
I want to remove empty/blank lines from comma seperated and space seperated files
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4. Shell Programming and Scripting
Hi,
how can i make a comma seperated output summary.
i attached the sample log file.
I have to capture these data in the log file.
Arcotid
Time Stamp, Username, Success, Failure, Error Code, Error Message
In the log snippet the userID can be found in-
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5. Shell Programming and Scripting
Dear All,
Good Day. I would like to hear your suggestions for the following problem:
I have a file with 5 columns with some numbers in 16 lines as shown below.
Input file:
Col 1 Col 2 Col 3 Col 4 Col 5
12 220 2 121 20
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6. Shell Programming and Scripting
Hi,
I have data like this.
1,2,3,4
Output required:
1
2
3
4
I am trying to use tr function but getting error.
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7. Shell Programming and Scripting
In the below awk the output is space delimited, but it should be tab delimited. Did I not add the correct -F and OFS? Thank you :).
The input file are rather large so I did not include them, but they are tab-delimeted files as well.
awk
awk -F'\t' -v OFS='\t' 'FNR==1 { next }
> ... (2 Replies)
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In the below awk written by @RavinderSingh13 I have added a few lines and am trying to have the output be tab-delimited. The input is space-delimeted and the portion in bold seems to add a tab to the Not found but not the found. Thank you :).
file1
One 1
Two 2
Three 3
file2
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Hi Experts
I have an escape seperated fields in the unix file. And in the below format file I need to extract the first column. Please help its urgent.
cat -v op.dat | head
24397028^
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24397028
2439707
thanks.
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10. UNIX for Beginners Questions & Answers
The awk below executes and produces the current output. it skips the header in row 1 and prints $4,$5,$6 and then adds the header row back.
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JOIN(1) General Commands Manual JOIN(1)
NAME
join - relational database operator
SYNOPSIS
join [ options ] file1 file2
DESCRIPTION
Join forms, on the standard output, a join of the two relations specified by the lines of file1 and file2. If file1 is `-', the standard
input is used.
File1 and file2 must be sorted in increasing ASCII collating sequence on the fields on which they are to be joined, normally the first in
each line.
There is one line in the output for each pair of lines in file1 and file2 that have identical join fields. The output line normally con-
sists of the common field, then the rest of the line from file1, then the rest of the line from file2.
Fields are normally separated by blank, tab or newline. In this case, multiple separators count as one, and leading separators are dis-
carded.
These options are recognized:
-an In addition to the normal output, produce a line for each unpairable line in file n, where n is 1 or 2.
-e s Replace empty output fields by string s.
-jn m Join on the mth field of file n. If n is missing, use the mth field in each file.
-o list
Each output line comprises the fields specified in list, each element of which has the form n.m, where n is a file number and m is a
field number.
-tc Use character c as a separator (tab character). Every appearance of c in a line is significant.
SEE ALSO
sort(1), comm(1), awk(1)
BUGS
With default field separation, the collating sequence is that of sort -b; with -t, the sequence is that of a plain sort.
The conventions of join, sort, comm, uniq, look and awk(1) are wildly incongruous.
7th Edition April 29, 1985 JOIN(1)