Sponsored Content
Top Forums Shell Programming and Scripting Grep with Regular expression now working on file directories Post 302963926 by Don Cragun on Friday 8th of January 2016 01:57:15 AM
Old 01-08-2016
What operating system and shell are you using? (As Scrutinizer said, the code he suggested with work with GNU grep. If you're not using a Linux system, there is a good chance that the grep you're using doesn't understand \b or \B.)
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

grep : regular expression

guys, my requirment goes like this: I have a file, and wish to filter out records where 1. The first letter is o or O and 2. The next 4 following letter should not be ther I do not wish to use pipe and wish to do it in one shot. The best expression I came up with is: grep ^*... (10 Replies)
Discussion started by: RishiPahuja
10 Replies

2. UNIX for Dummies Questions & Answers

Create directories with regular expression

Hi guys, can any one tell me how to create directories using regular expression? Let's say that I need to create directories test01, test02, test03.... test10. Can it be done using any regular expression? thanks. (13 Replies)
Discussion started by: mahendrt
13 Replies

3. Shell Programming and Scripting

regular expression not working.

Hi, I have to match a certain pattern of string in my shell script: 6.0.4.11.9 7.5.1.7.1 First Number can be 6 or 7 Second number can be 0 or 5 Rest all numbers can be between 1-99 I am using following egrep: egrep ^\.\.\.\.\$ filename But why is the above regular... (1 Reply)
Discussion started by: som.nitk
1 Replies

4. UNIX for Dummies Questions & Answers

using regular expression for directories in find command

Hi, I want to find the files available in a directory /var/user/*/*/data/. I tried using the command "find /var/user/ -path '*/*/data/ -name '*' -type f" it says find: 0652-017 -path is not a valid option and then i tried using "find /var/user/ -name '*/*/data/*' -type f" but its not... (3 Replies)
Discussion started by: vinothbabu12
3 Replies

5. Shell Programming and Scripting

grep and regular expression

Hi, I am executing a svnlook command to check to see if the following line exists. I need a regular expression to represent the line. A /test/test1/qa/test2/index.html A /test/test1/qa/test3/test.jpg A /test/test1/qa/test3/test1.jpg A /test/test1/qa/test4/test.swf I just need to extract... (9 Replies)
Discussion started by: kminkeller
9 Replies

6. Shell Programming and Scripting

Using grep and regular expression to find class references in a c++ file

I'm trying to math all class references in a C++ file using grep with regular expression. I'm trying to know if a specific include is usuless or not, so I have to know if there is a refence in cpp. I wrote this RE that searches for a reference from class ABCZ, but unfortunately it isn't working... (0 Replies)
Discussion started by: passerby
0 Replies

7. Shell Programming and Scripting

Help with grep / regular expression

Hi, Input file: -13- -1er- -1xyz1- -1xz12- -2ab1- -2ab2-- -143- Code: grep '^*\-' input.txt Wrong output: -13- -1xyz1- -2ab1- -2ab2-- (4 Replies)
Discussion started by: dragon.1431
4 Replies

8. Shell Programming and Scripting

Regular Expression not working with sed

Hi All, I am facing some problems with regular expression with sed. I have a .txt file with the contents as below: This is a dummy file # File created to test execution of regular expression. Hope it works out. As in the above contents there is a blank line which does not... (4 Replies)
Discussion started by: bghosh
4 Replies

9. Programming

Perl: How to read from a file, do regular expression and then replace the found regular expression

Hi all, How am I read a file, find the match regular expression and overwrite to the same files. open DESTINATION_FILE, "<tmptravl.dat" or die "tmptravl.dat"; open NEW_DESTINATION_FILE, ">new_tmptravl.dat" or die "new_tmptravl.dat"; while (<DESTINATION_FILE>) { # print... (1 Reply)
Discussion started by: jessy83
1 Replies

10. UNIX for Beginners Questions & Answers

SHELL: UNIX : Ls regular expression not working when used with variables

If i do below command in unix prompt which static values (ie 27..97), it is working fine and gives desired output >ls -d $WORKDIR/batch/somefilename_{27..97}.* 2>/dev/null somefilename_27.sometxt somefilename_28.sometxt somefilename_29.sometxt .. somefilename_97.sometxt But if i want... (2 Replies)
Discussion started by: haiderali
2 Replies
bup-margin(1)						      General Commands Manual						     bup-margin(1)

NAME
bup-margin - figure out your deduplication safety margin SYNOPSIS
bup margin [options...] DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids. For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by its first 46 bits. The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits, that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits with far fewer objects. If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if you're getting dangerously close to 160 bits. OPTIONS
--predict Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer from the guess. This is potentially useful for tuning an interpolation search algorithm. --ignore-midx don't use .midx files, use only .idx files. This is only really useful when used with --predict. EXAMPLE
$ bup margin Reading indexes: 100.00% (1612581/1612581), done. 40 40 matching prefix bits 1.94 bits per doubling 120 bits (61.86 doublings) remaining 4.19338e+18 times larger is possible Everyone on earth could have 625878182 data sets like yours, all in one repository, and we would expect 1 object collision. $ bup margin --predict PackIdxList: using 1 index. Reading indexes: 100.00% (1612581/1612581), done. 915 of 1612581 (0.057%) SEE ALSO
bup-midx(1), bup-save(1) BUP
Part of the bup(1) suite. AUTHORS
Avery Pennarun <apenwarr@gmail.com>. Bup unknown- bup-margin(1)
All times are GMT -4. The time now is 02:25 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy