Line by line getting a certain file name has a certain value
Hello
I have a file like this:
The first column is several file names in my directory and second column a number to detect some of them which is greater than 80%. So, I want to get the file names in the first column which are greater than 80%. How can I do that?
Please help!
Thank you
Last edited by Don Cragun; 01-03-2016 at 09:21 PM..
Reason: Add CODE tags.
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File 1
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<html>da ta 234 </html>
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234
542
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COLRM(1) BSD General Commands Manual COLRM(1)NAME
colrm -- remove columns from a file
SYNOPSIS
colrm [start [stop]]
DESCRIPTION
The colrm utility removes selected columns from the lines of a file. A column is defined as a single character in a line. Input is read
from the standard input. Output is written to the standard output.
If only the start column is specified, columns numbered less than the start column will be written. If both start and stop columns are spec-
ified, columns numbered less than the start column or greater than the stop column will be written. Column numbering starts with one, not
zero.
Tab characters increment the column count to the next multiple of eight. Backspace characters decrement the column count by one.
ENVIRONMENT
The LANG, LC_ALL and LC_CTYPE environment variables affect the execution of colrm as described in environ(7).
EXIT STATUS
The colrm utility exits 0 on success, and >0 if an error occurs.
SEE ALSO awk(1), column(1), cut(1), paste(1)HISTORY
The colrm command appeared in 3.0BSD.
BSD August 4, 2004 BSD