Hi everyone, this is my first post here, I hope someone can help me.
I have a file which I need to delete characters '_F3' from the end of the text in the first column. The problem is that the characters may also occur elsewhere in the file (i.e. second columns onwards). I tried sed (thinking I... (6 Replies)
I have an awk script to find the maximum value of the 2nd column of a 2 column datafile, but I need to find the top 5 maximum values of the 2nd column.
Here is the script that works for the maximum value.
awk 'BEGIN { subjectmax=$1 ; max=0} $2 >= max {subjectmax=$1 ; max=$2} END {print... (3 Replies)
Is there an awk script that can easily perform the following operation?
I have a data file that is in the format of
1944-12,5.6
1945-01,9.8
1945-02,6.7
1945-03,9.3
1945-04,5.9
1945-05,0.7
1945-06,0.0
1945-07,0.0
1945-08,0.0
1945-09,0.0
1945-10,0.2
1945-11,10.5
1945-12,22.3... (3 Replies)
Hi,
I need an awk script (or whatever shell-construct) that would take data like below and get the max value of 3 column, when grouping by the 1st column.
clientname,day-of-month,max-users
-----------------------------------
client1,20120610,5
client2,20120610,2
client3,20120610,7... (3 Replies)
Hello,
i have the following code :
somevariable=`mysql -u root --password="" databasename -e "select count(column_name) from table_name where id=1 and id_age=2 ; " --skip-column-names -s -N`
if ]
then ....
It gives the message
")syntax error: invalid arithmetic operator (error... (2 Replies)
Hello Members,
I have a csv file in the format below. Need help with awk statement to break nth column into 3 separate columns and export the changes to new file.
input file --> file.csv
cat file.csv|less
"product/fruit/mango","location/asia/india","type/alphonso"
need output in... (2 Replies)
Hi,
My input files is like this
axis1 0 1 10
axis2 0 1 5
axis1 1 2 -4
axis2 2 3 -3
axis1 3 4 5
axis2 3 4 -1
axis1 4 5 -6
axis2 4 5 1
Now, these are my following tasks
1. Print a first column for every two rows that has the same value followed by a string.
2. Match on the... (3 Replies)
I need to be able to search for a string in the first column and if that string exists than replace the nth column with "-9.99".
AW12000012012 2.38 1.51 3.01 1.66 0.90 0.91 1.22 0.82 0.57 1.67 2.31 3.63 0.00
AW12000012013 1.52 0.90 1.20 1.34 1.21 0.67 ... (14 Replies)
I am passing a variable and replace nth value with the variable.
I tried using many options in awk command but unable to ignore the special characters in the output and also unable to pass the actual value.
Input : "1","2","3"
Output : "1","1000","3"
TempVal=`echo 1000`
Cat... (2 Replies)
Hi guys,
I have problem to append new data at the end of each line of the files where it takes whole value of the nth column. My expected result i just want to take a specific value only. This new data is based on substring of 11th, 12th 13th column that has comma seperated value.
My code:
awk... (4 Replies)
Discussion started by: null7
4 Replies
LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1)NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS --predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO bup-midx(1), bup-save(1)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-margin(1)