Sponsored Content
Top Forums UNIX for Dummies Questions & Answers Basic arithmetic operation with awk? Post 302962831 by Don Cragun on Friday 18th of December 2015 10:29:12 PM
Old 12-18-2015
Is this a homework assignment? (Homework and coursework questions can only be posted in the Homework & Coursework forum with a completely filled out template from the special homework rules described here.)

I have no idea what you are trying to do. Arithmetic operators (except unary minus) work on two operands. Therefore, a arithmetic formula has one more operand than there are operators. But, your example has 3 operands and 3 operators.

Are you saying that you want each number to have a trailing + or - sign to indicate whether the number is positive or negative and you then want to add up all of the signed numbers?

Are you only processing single-digit numbers?
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Simple arithmetic operation

I have no idea why I can't get this to work, if anybody can help i would appreciate it. #!/bin/bash x=`cat counter.txt | wc -l` y= '$x / 7' printf "%d People have visited this page" $y :confused: (2 Replies)
Discussion started by: paladyn_2002
2 Replies

2. Shell Programming and Scripting

Help with arithmetic operation

I am using egrep to extract numbers from a file and storing them as variables in a script. But I am not able to do any arithmetic operations on the variables using "expr" because it stores them as char and not integers. Here is my code and the error I get. Any help will be appreciated. #!/bin/sh... (3 Replies)
Discussion started by: emjayshaikh
3 Replies

3. UNIX for Dummies Questions & Answers

arithmetic operation on two columns

Hi, All, I have a file, its content is as follows: 100 150 120 135 140 170 I want to insert a column, its content is determined by the difference between the two values in the same line, if the difference is less than 20, the new value is 1, otherwise is 0. after the operation, the... (1 Reply)
Discussion started by: Jenny.palmy
1 Replies

4. Shell Programming and Scripting

How to perform arithmetic operation on date

Hi all, I would appreciate if anyone knows how to perform adding to date. As for normal date, i can easily plus with any number. But when it comes to month end say for example 28 Jun, i need to perform a plus with number 3, it will not return 1 Jul. Thanks in advance for your help. (4 Replies)
Discussion started by: agathaeleanor
4 Replies

5. Shell Programming and Scripting

Arithmetic operation with awk

I have output like following in a file usmtnz-dinfsi19 72 71 38 1199 1199 0.8 19:23:58 usmtnz-dinfsi19 72 71 38 1199 1199 0.8 19:24:04 (9 Replies)
Discussion started by: fugitive
9 Replies

6. Shell Programming and Scripting

Arithmetic operation between columns using loop variable

Hi I have a file with 3 columns. say, infile: 1 50 68 34 3 23 23 4 56 ------- ------- I want to generate n files from this file using a loop so that 1st column in output file is (column1 of infile/(2*n+2.561)) I am doing like this: for ((i=1; i<=3; i++)) do a=`echo... (3 Replies)
Discussion started by: Surabhi_so_mh
3 Replies

7. Shell Programming and Scripting

floating point arithmetic operation error

I am writing a script in zsh shell, it fetchs a number from a file using the awk command, store it as a variable, which in my case is a small number 0.62000. I want to change this number by multiplying it by 1000 to become 620.0 using the command in the script var2=$((var1*1000)) trouble is... (2 Replies)
Discussion started by: piynik
2 Replies

8. Shell Programming and Scripting

Arithmetic operation in variable

Hi, Here is the script i try to perform arithmetic operation in two variables . git branch -r | while read brname ; do REV_COMMITS=`git rev-list --count $brname` echo "$brname has $REV_COMMITS" (( TOTAL = TOTAL + REV_COMMITS )) echo "in loop" $TOTAL done echo "total is " $TOTAL ... (3 Replies)
Discussion started by: greet_sed
3 Replies

9. Shell Programming and Scripting

Using awk to do arithmetic operation

Hi, I've this following text file FileVersion = 1.03 Filetype = meteo_on_curvilinear_grid TIME = 0 hours since 2016-10-03 12:00:00 +00:00 -6.855 -6.828 -6.801 -6.774 -6.747 -6.719 -6.691 -6.663 -6.634 -6.606 -6.577 -6.548 -6.519 -6.489 TIME = 0 hours since... (2 Replies)
Discussion started by: xisan
2 Replies

10. How to Post in the The UNIX and Linux Forums

How to get defined precision after arithmetic operation using syncsort?

I have to do some arithmetic operation on Field 8 which is calculated by Field 9/Field 7 Suppose i have data like : 0800123456|JAN|2017|JAN|2018|0800123456|0|0.0000|0.00| 0800234567|JAN|2017|JAN|2018|0800234567|4|2.5812|10.32| 0800666666|JAN|2017|JAN|2018|0800666666|2|1.7255|3.45|... (0 Replies)
Discussion started by: pumrao
0 Replies
bup-margin(1)						      General Commands Manual						     bup-margin(1)

NAME
bup-margin - figure out your deduplication safety margin SYNOPSIS
bup margin [options...] DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids. For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by its first 46 bits. The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits, that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits with far fewer objects. If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if you're getting dangerously close to 160 bits. OPTIONS
--predict Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer from the guess. This is potentially useful for tuning an interpolation search algorithm. --ignore-midx don't use .midx files, use only .idx files. This is only really useful when used with --predict. EXAMPLE
$ bup margin Reading indexes: 100.00% (1612581/1612581), done. 40 40 matching prefix bits 1.94 bits per doubling 120 bits (61.86 doublings) remaining 4.19338e+18 times larger is possible Everyone on earth could have 625878182 data sets like yours, all in one repository, and we would expect 1 object collision. $ bup margin --predict PackIdxList: using 1 index. Reading indexes: 100.00% (1612581/1612581), done. 915 of 1612581 (0.057%) SEE ALSO
bup-midx(1), bup-save(1) BUP
Part of the bup(1) suite. AUTHORS
Avery Pennarun <apenwarr@gmail.com>. Bup unknown- bup-margin(1)
All times are GMT -4. The time now is 02:26 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy