Hello, I am a beginner to shell programming. Coded the following for Fibonacci series.
The program is going into infinite loop. From debugging I understood that updated i,j values are not being carried to next iteration of while loop. Why is it so? Can someone please help.
Last edited by Don Cragun; 12-09-2015 at 02:55 PM..
Reason: Add CODE and ICODE tags.
hi,
I'm a beginner to UNIX and got some problem in this fibonacci.Please help me out.Here is the code:
fibo()
{
if
then
fibo=` expr {fibo ($1 - 2)} + {fibo ($1 - 1)}` | bc
echo $fibo
fi
}
echo "enter a number:"
read x
#echo "The fibonnacci series for value $x is:"
fibo $x
... (4 Replies)
Hi guys, I'm having a problem getting my infinite loop to loop. It simply reads in the users choice form the menu, executes the corresponding case statement and quits instead of looping back to the main menu again. I have a feeling it might be something with my if then statements within the case... (2 Replies)
hi all,
this is how my scrip looks like
#!/bin/sh
bindir='/opt/apps/script/bin'
datadir='/opt/apps/script/data'
dir='/opt/apps/script'
while : ; do
ls -1rt /opt/apps/script/data/check.txt*|tail -1 > /dev/null 2>&1
if ;then
chmod +rwx $bindir/dummy2.sh
... (8 Replies)
I am facing problem with Shell script to generate Fibonacci series using recursion i.e. recursive function.
Here is my script:
#!/bin/sh
fibo()
{
no=$1
if ; then
return 0
elif ; then
return 1
else
a1=`expr $no - 1`
fibo $a1
... (10 Replies)
Use and complete the template provided. The entire template must be completed. If you don't, your post may be deleted!
1. The problem statement, all variables and given/known data:
Shell script to find sum of first n numbers of Fibonacci series
2. Relevant commands, code, scripts,... (0 Replies)
I wanted to copy (not forward but copy) all incoming email to another address of mine. It worked, but now I encountered an infinite loop problem: When the second address doesn't like the content and bounces the message back, the bounce message will be sent back and forth.
So, what I have in... (1 Reply)
Hi, I was debating if I should put this in the dummies or scripts section, I apologize in advance if I chose poorly.
Fairly new to Unix and BASH scripting but I thought I made it fairly well given my limited understanding. However, the output indicates that it's looping and I'm ending up with a... (5 Replies)
I have a script script.shwhich is scheduled to run at 11 AM everyday.
# script.sh Code:
./scb_script.sh &
unfortunately scb_script.sh is running today in infinite loop as respective files are not available.
My question, when script.sh starts running tomorrow, will the old process be... (1 Reply)
Discussion started by: JSKOBS
1 Replies
LEARN ABOUT BSD
expr
EXPR(1) General Commands Manual EXPR(1)NAME
expr - evaluate arguments as an expression
SYNOPSIS
expr arg ...
DESCRIPTION
The arguments are taken as an expression. After evaluation, the result is written on the standard output. Each token of the expression is
a separate argument.
The operators and keywords are listed below. The list is in order of increasing precedence, with equal precedence operators grouped.
expr | expr
yields the first expr if it is neither null nor `0', otherwise yields the second expr.
expr & expr
yields the first expr if neither expr is null or `0', otherwise yields `0'.
expr relop expr
where relop is one of < <= = != >= >, yields `1' if the indicated comparison is true, `0' if false. The comparison is numeric if
both expr are integers, otherwise lexicographic.
expr + expr
expr - expr
addition or subtraction of the arguments.
expr * expr
expr / expr
expr % expr
multiplication, division, or remainder of the arguments.
expr : expr
The matching operator compares the string first argument with the regular expression second argument; regular expression syntax is
the same as that of ed(1). The (...) pattern symbols can be used to select a portion of the first argument. Otherwise, the
matching operator yields the number of characters matched (`0' on failure).
( expr )
parentheses for grouping.
Examples:
To add 1 to the Shell variable a:
a=`expr $a + 1`
To find the filename part (least significant part) of the pathname stored in variable a, which may or may not contain `/':
expr $a : '.*/(.*)' '|' $a
Note the quoted Shell metacharacters.
SEE ALSO sh(1), test(1)DIAGNOSTICS
Expr returns the following exit codes:
0 if the expression is neither null nor `0',
1 if the expression is null or `0',
2 for invalid expressions.
7th Edition April 29, 1985 EXPR(1)