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Top Forums Shell Programming and Scripting Count delimiter(~|*) each row in a file and return 1 or 0 Post 302958739 by Don Cragun on Monday 26th of October 2015 05:05:33 AM
Old 10-26-2015
The asterisk has special meaning in an ERE too.

Assuming you aren't on a Solaris/SunOS system, try:
Code:
awk -F '~\|\*' 'NF != 4 {delim_flag=1; exit} END{printf("%d\n", delim_flag}' "filename.txt"

 

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SETCAP(8)						      System Manager's Manual							 SETCAP(8)

NAME
setcap - set file capabilities SYNOPSIS
setcap [-q] [-v] (capabilities|-|-r) filename [ ... capabilitiesN fileN ] DESCRIPTION
In the absence of the -v (verify) option setcap sets the capabilities of each specified filename to the capabilities specified. The -v option is used to verify that the specified capabilities are currently associated with the file. The capabilities are specified in the form described in cap_from_text(3). The special capability string, '-', can be used to indicate that capabilities are read from the standard input. In such cases, the capabil- ity set is terminated with a blank line. The special capability string, '-r', is used to remove a capability set from a file. The -q flag is used to make the program less verbose in its output. EXIT CODE
The setcap program will exit with a 0 exit code if successful. On failure, the exit code is 1. SEE ALSO
cap_from_text(3), cap_set_file(3), getcap(8) 24th October 2008 SETCAP(8)
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