removing a delimiter at the start of row

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# 1  
Old 10-24-2007
removing a delimiter at the start of row

I Have this code

while [ ${iCount1} -le ${reccount} ]


column1=":`cat /home/test_inter.txt|head -${iCount1}|tail -1|cut -d "," -f2`"


iCount1=`expr ${iCount1} + 1`


echo $columnA

The output of this code is coming as


A colon(Smilie at the beginning of each row I am using this colon as a field delimiter. But I don't want it at the beginning of each row.

Any help regarding this?
# 2  
Old 10-24-2007
Not a very efficient solution:
echo ":1:2:2:3:3:4" |  cut -c 2-

Get everything from second character onwards
# 3  
Old 10-24-2007
The reason is, that you preceed EACH field with a colon in the "column1=...." line. Since you do this in a loop anyways (i'm pretty sure you could achieve this more easily, but that only as a aside) start without the colon and only add the colon from field 2 onwards. Oh, by the way: backticks are OUT and "expr" is unnecessary in ksh:

column1="$(cat /home/test_inter.txt|head -1|tail -1|cut -d "," -f2)"
while [ ${iCount1} -le ${reccount} ] ; do

     column1="${column1}:$( cat /home/test_inter.txt |\
                            head -${iCount1} |\
                            tail -1 |\
                            cut -d "," -f2 \

     (( iCount1++ ))


echo $column1

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