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Top Forums UNIX for Dummies Questions & Answers sed question Post 302958351 by MadeInGermany on Wednesday 21st of October 2015 12:07:26 PM
Old 10-21-2015
Quote:
Originally Posted by jimmyf
Trying to write a sed replacement but the command is taking some characters as literal. Here is what I have:
Code:
Text 100 101

. This is desired output:
Code:
['Text' 100,101]

. This is what I have so far:
Code:
sed 's/^[A-Z]/[&/g;s/[a-z] /&] /g'

. Any help would be greatly appreciated.
You face the problem how to put a ' character within a 'string_in_ticks'
Either use the ' within "quotes" or escape it with '\''.
Then you have the problem of matching [a-z] and putting a ] character in between. For this you can enclose a part with \( \) and use a \1 reference (and a \2 reference for the next \( \)).
Last but not least, you don't need /g option (repeated substitution attempts per line).
Code:
sed "s/^[A-Z]/['&/; s/\([a-z]\) /\1'] /"

Code:
sed 's/^[A-Z]/['\''&/; s/\([a-z]\) /\1'\''] /'

Colors demonstrate that in the shell the 'string' is split into parts, and the escaped ' are outside the 'strings'.
Code:
sed 's/^[A-Z]/['\''&/; s/\([a-z]\) /\1'\''] /'

--
Just seeing you want the ] at the very end. Then have a third substitution.
Code:
sed 's/^[A-Z]/['\''&/; s/\([a-z]\) /\1'\'' /; s/$/]/'

The good thing with $ is that it does not match a real character so you do not need to put it back.

Last edited by MadeInGermany; 10-21-2015 at 01:23 PM..
 

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