Difference between two date values Post: 302957624

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Top Forums UNIX for Dummies Questions & Answers Difference between two date values Post 302957624 by RavinderSingh13 on Tuesday 13th of October 2015 10:16:13 AM

10-13-2015

Moderator

Quote:

Originally Posted by sam@sam

Code:

bash-3.00$ date

Tue Oct 13 15:03:54 CEST 2015

Code:

start=`date +"%T" | awk -F":" '{print $2,$3}'`
echo $start

08 17

Code:

end=`date +"%T" | awk -F":" '{print $2,$3}'`
echo $end

08 37
how can I difference between above both times, Im trying but getting errors:

Code:

bash-3.00$ echo `expr $end - $start`

expr: syntax error

Code:

bash-3.00$ echo  $(($end - $start))

bash: 08: value too great for base (error token is "08")
expected output for this case should be something like 00 20

Hello sam@sam,

Could you please try following and let us know if this helps.

Code:

START=`date +"%T" | awk -F":" '{print $2 FS $3}'`
##### I ran following command after few mins
END=`date +"%T" | awk -F":" '{print $2 FS $3}'`
##### Then use following awk command to calculate difference.
awk -vstart=$START -vend=$END 'BEGIN{split(start, A,":");split(end, B,":");sec_start=A[1] * 60 + A[2];sec_end=B[1] * 60 + B[2];diff=sec_end - sec_start;print "Minutes \t Seconds" ORS int(diff/60) "\t\t " diff%60}'

You could use this in script too as per your convenience too.
NOTE: It is only looking for taking difference of minutes and seconds not dates.

Thanks,
R. Singh

Last edited by RavinderSingh13; 10-13-2015 at 11:45 AM..

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