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Full Discussion: Issue using empty variable in grep command
Top Forums Shell Programming and Scripting Issue using empty variable in grep command Post 302956967 by mbak on Monday 5th of October 2015 02:21:31 PM
Old 10-05-2015
Issue using empty variable in grep command
I'm trying to enhance the script i.e., if there is more than one value for DISK variable but it errors out on nested "for loop" saying "0403-057 Syntax error at line 13 : `for' is not matched"


Code:
for i in `
    for DISK in `awk '/disk/ {print substr($1, 7)}' /tmp/list.out`
    do
        if [ -z "$DISK" ]
        then
           lspv | awk '{print$1}'
        else
           lspv | awk '{print$1}' | grep -vw "$DISK"
        fi
    done
`
do
  .....
done

 

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LEARN ABOUT HPUX

zgrep

ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME

       zgrep - search possibly compressed files for a regular expression

SYNOPSIS

       zgrep [ grep_options ] [ -e ] pattern filename...

DESCRIPTION

       Zgrep  invokes  grep  on  compressed  or  gzipped  files.   These  grep	options  will  cause  zgrep  to  terminate  with  an  error  code:
       (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*).  All other options specified are passed directly to grep.  If no file is specified,  then  the
       standard input is decompressed if necessary and fed to grep.  Otherwise the given files are uncompressed if necessary and fed to grep.

       If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.

EXIT CODE

       2 - An option that is not supported was specified.

AUTHOR

       Charles Levert (charles@comm.polymtl.ca)

SEE ALSO

       grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)

																	  ZGREP(1)
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