10-05-2015
Quote:
Originally Posted by
prince1987
Do you know any commands in UNIX without perl script? For example if its 25 hours, then our result should be.
1day,1hour,0min,0sec.
Appreciate your help!
Thanks
---------- Post updated at 09:11 AM ---------- Previous update was at 09:04 AM ----------
Can you calculate with 1443929685, For example if its 25 hours, then our result should be.
1day,1hour,0min,0sec.
Appreciate your help!
Thanks
It appears you are confusing what epoch time is. That 1443929685 is the representation in seconds of a specific time; in this case
Sat Oct 3 21:34:45 2015 in my timezone
There is not way of getting
1day,1hour,0min,0sec unless you are computing the difference against another time.
Please, mention what shell you are using if you do not want to use Perl.
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LEARN ABOUT SUSE
time::julianday
Time::JulianDay(3) User Contributed Perl Documentation Time::JulianDay(3)
NAME
Time::JulianDay -- Julian calendar manipulations
SYNOPSIS
use Time::JulianDay
$jd = julian_day($year, $month_1_to_12, $day)
$jd = local_julian_day($seconds_since_1970);
$jd = gm_julian_day($seconds_since_1970);
($year, $month_1_to_12, $day) = inverse_julian_day($jd)
$dow = day_of_week($jd)
print (Sun,Mon,Tue,Wed,Thu,Fri,Sat)[$dow];
$seconds_since_jan_1_1970 = jd_secondslocal($jd, $hour, $min, $sec)
$seconds_since_jan_1_1970 = jd_secondsgm($jd, $hour, $min, $sec)
$seconds_since_jan_1_1970 = jd_timelocal($sec,$min,$hours,$mday,$month_0_to_11,$year)
$seconds_since_jan_1_1970 = jd_timegm($sec,$min,$hours,$mday,$month_0_to_11,$year)
DESCRIPTION
JulianDay is a package that manipulates dates as number of days since some time a long time ago. It's easy to add and subtract time using
julian days...
The day_of_week returned by day_of_week() is 0 for Sunday, and 6 for Saturday and everything else is in between.
ERRATA
Time::JulianDay is not a correct implementation. There are two problems. The first problem is that Time::JulianDay only works with
integers. Julian Day can be fractional to represent time within a day. If you call inverse_julian_day() with a non-integer time, it will
often give you an incorrect result.
The second problem is that Julian Days start at noon rather than midnight. The julian_day() function returns results that are too large by
0.5.
What to do about these problems is currently open for debate. I'm tempted to leave the current functions alone and add a second set with
more accurate behavior.
There is another implementation in Astro::Time that may be more accurate.
GENESIS
Written by David Muir Sharnoff <muir@idiom.com> with help from previous work by Kurt Jaeger aka PI <zrzr0111@helpdesk.rus.uni-stuttgart.de>
based on postings from: Ian Miller <ian_m@cix.compulink.co.uk>; Gary Puckering <garyp%cognos.uucp@uunet.uu.net> based on
Collected Algorithms of the ACM ?; and the unknown-to-me author of Time::Local.
LICENSE
Copyright (C) 1996-1999 David Muir Sharnoff. License hereby granted for anyone to use, modify or redistribute this module at their own
risk. Please feed useful changes back to muir@idiom.com.
perl v5.12.1 2004-02-08 Time::JulianDay(3)