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Top Forums Shell Programming and Scripting Can anyone help me to print UNIX epoch time to days,hours,min,sec ? Post 302956854 by Aia on Monday 5th of October 2015 12:49:32 AM
Old 10-05-2015
Quote:
Originally Posted by prince1987
Do you know any commands in UNIX without perl script? For example if its 25 hours, then our result should be.

1day,1hour,0min,0sec.

Appreciate your help!
Thanks

---------- Post updated at 09:11 AM ---------- Previous update was at 09:04 AM ----------

Can you calculate with 1443929685, For example if its 25 hours, then our result should be.

1day,1hour,0min,0sec.

Appreciate your help!
Thanks
It appears you are confusing what epoch time is. That 1443929685 is the representation in seconds of a specific time; in this case Sat Oct 3 21:34:45 2015 in my timezone
There is not way of getting 1day,1hour,0min,0sec unless you are computing the difference against another time.
Please, mention what shell you are using if you do not want to use Perl.
 

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SHELL-QUOTE(1p) 					User Contributed Perl Documentation					   SHELL-QUOTE(1p)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)
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